Back
to top
Quick dirac notation question
Watch this thread
Announcements
Page 1 of 1
Go to first unread
Skip to page:
QuantumOverlord
Badges:
16
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
Annoyed with myself for forgetting this, I just want to check this is okay.
<Q|AB|P>=<Q|A|P><Q|B|P>
The context is Nuclear physics. I am trying to get the expectation of the magnetic moment of the nucleus <u>. It works if <J|(g_nucleus)J|J>=<J|(g_nucleus)|J><J|J|J>
<Q|AB|P>=<Q|A|P><Q|B|P>
The context is Nuclear physics. I am trying to get the expectation of the magnetic moment of the nucleus <u>. It works if <J|(g_nucleus)J|J>=<J|(g_nucleus)|J><J|J|J>
0
reply
WishingChaff
Badges:
2
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
You should use the identity operator to split bra-ket in this manner.
Using
you can insert this into you equation to give:
You can obviously use a continuous version, providing you pick the correct eigenstates.
Using
you can insert this into you equation to give:You can obviously use a continuous version, providing you pick the correct eigenstates.
(Original post by QuantumOverlord)
Annoyed with myself for forgetting this, I just want to check this is okay.
<Q|AB|P>=<Q|A|P><Q|B|P>
The context is Nuclear physics. I am trying to get the expectation of the magnetic moment of the nucleus <u>. It works if <J|(g_nucleus)J|J>=<J|(g_nucleus)|J><J|J|J>
Annoyed with myself for forgetting this, I just want to check this is okay.
<Q|AB|P>=<Q|A|P><Q|B|P>
The context is Nuclear physics. I am trying to get the expectation of the magnetic moment of the nucleus <u>. It works if <J|(g_nucleus)J|J>=<J|(g_nucleus)|J><J|J|J>
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
