The Student Room Group

Indices Equation

Hi, I'm unsure how to proceed witht the following question...


x^2/3 + (3*root3)x^1/3 - 30 = 0

So I think multiple all three terms to a power of 3 to rid the fractional powers?

x^2 + (3*root3)x - 27000 = 0


Is this correct so far?
I'm thinking (3*root3) needs to be cubed aswell? If so how?

Then following this, what would be the next stage?



Thanks for any help in the right direction..
Original post by nicevans1
Hi, I'm unsure how to proceed witht the following question...


x^2/3 + (3*root3)x^1/3 - 30 = 0

So I think multiple all three terms to a power of 3 to rid the fractional powers?

x^2 + (3*root3)x - 27000 = 0


Is this correct so far?
I'm thinking (3*root3) needs to be cubed aswell? If so how?

Then following this, what would be the next stage?



Thanks for any help in the right direction..


You can rewrite x^2/3 + (3*root3)x^1/3 - 30 = 0 as

(x1/3)2+33(x1/3)30=0\left( x^{1/3} \right)^2 + 3 \sqrt{3}(x^{1/3})-30=0

Cubing everything is not a valid step.

For example 2+3=5 but 23+33532^3+3^3 \ne 5^3
Reply 2
Original post by BuryMathsTutor


(x1/3)2+33(x1/3)30=0\left( x^{1/3} \right)^2 + 3 \sqrt{3}(x^{1/3})-30=0

Cubing everything is not a valid step.


Ok i understand you cant cube everything.

Im here so far!

(x^1/3 + ) (x^1/3 - )

how do you work out what adds to = 3*root3 and multiplies to = 30?

Thanks
Original post by nicevans1
Ok i understand you cant cube everything.

Im here so far!

(x^1/3 + ) (x^1/3 - )

how do you work out what adds to = 3*root3 and multiplies to = 30?

Thanks


Use the quadratic formula

Quick Reply

Latest