What do we know?
Let X be the percentage of B-10.
Therefore 100-X is the percentage of B-11
Now you know the equation:
Average Mr= (Mr(B-10)*(percentage abundance)+ Mr(b-11) * (percentage abundance))/100
Subbing in:
10.8 = (10*X+11*(100-X))/100
Posted from TSR Mobile
Let X be the percentage of B-10.
Therefore 100-X is the percentage of B-11
Now you know the equation:
Average Mr= (Mr(B-10)*(percentage abundance)+ Mr(b-11) * (percentage abundance))/100
Subbing in:
10.8 = (10*X+11*(100-X))/100
Posted from TSR Mobile
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