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Logarithm equation help
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SteveMcs
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#1
Having some trouble with one question to do with logs.
(note, logs are all to the base 10)
Solve for x:
log(19x) = 3.9 - 2.1x
I just don't know how to tackle it with the "non-logged" x on the RHS
if it was just logA = B i would say A = 10^B but that doesn't help me find what x is.
I'm not asking anyone to do the question for me, but a step in the right direction would be appreciated.
(note, logs are all to the base 10)
Solve for x:
log(19x) = 3.9 - 2.1x
I just don't know how to tackle it with the "non-logged" x on the RHS
if it was just logA = B i would say A = 10^B but that doesn't help me find what x is.
I'm not asking anyone to do the question for me, but a step in the right direction would be appreciated.
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TenOfThem
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#2
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#2
(Original post by SteveMcs)
Having some trouble with one question to do with logs.
(note, logs are all to the base 10)
Solve for x:
log(19x) = 3.9 - 2.1x
I just don't know how to tackle it with the "non-logged" x on the RHS
if it was just logA = B i would say A = 10^B but that doesn't help me find what x is.
I'm not asking anyone to do the question for me, but a step in the right direction would be appreciated.
Having some trouble with one question to do with logs.
(note, logs are all to the base 10)
Solve for x:
log(19x) = 3.9 - 2.1x
I just don't know how to tackle it with the "non-logged" x on the RHS
if it was just logA = B i would say A = 10^B but that doesn't help me find what x is.
I'm not asking anyone to do the question for me, but a step in the right direction would be appreciated.
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SteveMcs
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#3
(Original post by TenOfThem)
Are you sure that this is the question as it would be solved using numerical rather than algebraic methods
Are you sure that this is the question as it would be solved using numerical rather than algebraic methods
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TenOfThem
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#4
(Original post by SteveMcs)
100% sure. Only way i could think was by graphing both sides and giving an approximation but they want the answer to 2 dp. I don't think i'd be able to give an approximation that accurate.
100% sure. Only way i could think was by graphing both sides and giving an approximation but they want the answer to 2 dp. I don't think i'd be able to give an approximation that accurate.
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SteveMcs
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#5
This isn't actually for my course. I'm doing BSc Actuarial Science. But this is for my partner who's doing a Numerical Skills for Scientists module in Environmental Earth Science
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SteveMcs
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#6
I got the answer in this example to be 1.21 to 2dp as there is a sign change when subbing x=1.205 and x=1.21. There's got to be an easier way of solving this?
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davros
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(Original post by SteveMcs)
I got the answer in this example to be 1.21 to 2dp as there is a sign change when subbing x=1.205 and x=1.21. There's got to be an easier way of solving this?
I got the answer in this example to be 1.21 to 2dp as there is a sign change when subbing x=1.205 and x=1.21. There's got to be an easier way of solving this?
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Mr M
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#8
(Original post by SteveMcs)
I got the answer in this example to be 1.21 to 2dp as there is a sign change when subbing x=1.205 and x=1.21. There's got to be an easier way of solving this?
I got the answer in this example to be 1.21 to 2dp as there is a sign change when subbing x=1.205 and x=1.21. There's got to be an easier way of solving this?
.In the case a suitable rearrangement is
Type 1 = into your calculator.
Now type
and press = a few times.
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