The Student Room Group

Mathematicians - Help Please!!!!

Coordinate geometry. :s-smilie:

1) Given that the straight line passing through the points A(2,-3) and B(7,K) has gradient 3/2...

a) find the value of k.
b) show that the perpendicular bisector of AB has the equation 8x+12y-45 = 0.

2) The verticles of a triangle are the points A(5,4), B(-5,8)
and C(1,11)..

a) Find the equation of the straight line passing through A and B, giving your answer in the form ax+by+c = 0.
b) Find the coordinates of the point M, the mid-point of AC.


thanks in advance.
Reply 1
1) Given that the straight line passing through the points A(2,-3) and B(7,K) has gradient 3/2...

Use the equation

Unparseable latex formula:

\tex \large M = \frac{Y_1 - Y_2}{X_1 - X_2}



where m = gradient and the coordinates (x1,y1) and (x2,y2)

b)show that the perpendicular bisector of AB has the equation 8x+12y-45 = 0.

Find the midpoint of the line AB using the equation
Unparseable latex formula:

\tex \large Midpoint = (\frac{x1+x2}{2},\frac{y1+y2}{2})



Then find the perpendicular gradient and use the equation yy1=m(xx1) y - y_1 = m(x-x_1)
Theres the first questions hints

2) The verticles of a triangle are the points A(5,4), B(-5,8)
and C(1,11)..

a) Find the equation of the straight line passing through A and B, giving your answer in the form ax+by+c = 0.
Find the gradient between A and B using
Unparseable latex formula:

\tex \large M = \frac{Y_1 - Y_2}{X_1 - X_2}

then use the equation yy1=m(xx1) y - y_1 = m(x-x_1) .

b) Find the coordinates of the point M, the mid-point of AC.

use the equation

Unparseable latex formula:

\tex \large Midpoint = (\frac{x1+x2}{2},\frac{y1+y2}{2})




It really helps if you know these equations.

If you need more help just ask.
Reply 2
1a) 3/2 = (k - -3)/ (7 - 2)


... stuck already!
Reply 3
well you know that 7-2 = 5

whats k--3 = ?

then its just a simple algebraic manipulation question.
k+3 because (-) (-) means (+)
(edited 3 years ago)