# AH Physics 2002 paper questionWatch

#1
2.(b) (i)-

"The orbital periood of a geostationary satellite is equal to the period of the rotation of the Earth about it's axis.

calculate the height of the satellite above the Earth's surface."

When I tried this problem it just seemed to throw the radius of the Earth back at me. How can I solve this.
0
12 years ago
#2
I think what ur doing wrong is forgetting to take the earths radius off the answer.

r3 =(GMe/4piÂ²)TÂ²
r3=(6.67x10^-11 x 6x10^24 x (86400)Â²)/4piÂ²
r3=7.567x10^22
r= 422397523

To get height above earth take off earths radius(6.4x10^6)

r = 3.6x10^7m
0
#3
Im not given the time in the question though.
0
12 years ago
#4
Its a geostationary satellite and therefore has a 24 hour orbit. You are expected to remember that from standard grade.

24x60x60 = 86400 seconds
0
#5
yeah I know, didnt realize that. I knew what geostationary meant.
0
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