Tricky method of differences FP2 question.

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Damien_Dalgaard
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Exercise A Question 5.

Partial fractions = (2/r) + (1/(r+1)) - 3/(r+2)

Stuck on the second, I can't see the pattern.

Thanks guys.
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Puddles the Monkey
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(Original post by Damien_Dalgaard)

Exercise A Question 5.

Partial fractions = (2/r) + (1/(r+1)) - 3/(r+2)

Stuck on the second, I can't see the pattern.

Thanks guys.
Heya, I'm going to put this in the Maths forum for you as you should get more responses there.

You should also check out the forum to see if there's any other threads there which might be helpful to you!

http://www.thestudentroom.co.uk/forumdisplay.php?f=38
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ghostwalker
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(Original post by Damien_Dalgaard)
https://8fd9eafbb84fdb32c73d8e44d980...lZweHc/CH2.pdf

Exercise A Question 5.

Partial fractions = (2/r) + (1/(r+1)) - 3/(r+2)

Stuck on the second, I can't see the pattern.

Thanks guys.
Consecutive numerators are 2,1,-3, so stick them in a table (you'll have to imagine it having more columns/rows):

\begin{matrix} 2 & 1 & -3 & & & & \\ & 2 & 1 & -3 & & \\ & & 2 & 1 & -3 & \\ & & &   2 & 1 & -3\end{matrix}

And add the colums (these correspond to the same denominator).

Everything cancels, except two terms at the start, and two at the end.
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Gome44
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(Original post by Damien_Dalgaard)

Exercise A Question 5.

Partial fractions = (2/r) + (1/(r+1)) - 3/(r+2)

Stuck on the second, I can't see the pattern.

Thanks guys.
This is strange. I assume you're using the FP2 book by Keith Pledger. If so, this is my question 5 in the exercise Name:  ImageUploadedByStudent Room1424715708.016681.jpg
Views: 193
Size:  70.9 KB

Also, although this is probably not the best practise for fp2, the question says 'or otherwise' which means you could do it by induction
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davros
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(Original post by Gome44)
This is strange. I assume you're using the FP2 book by Keith Pledger. If so, this is my question 5 in the exercise Name:  ImageUploadedByStudent Room1424715708.016681.jpg
Views: 193
Size:  70.9 KB

Also, although this is probably not the best practise for fp2, the question says 'or otherwise' which means you could do it by induction
The question the OP is tackling is contained in the pdf file attached to the original post. Strangely, it seems to be a SolutionBank with solutions to every question except the one the OP is doing!
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Damien_Dalgaard
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(Original post by Gome44)
This is strange. I assume you're using the FP2 book by Keith Pledger. If so, this is my question 5 in the exercise Name:  ImageUploadedByStudent Room1424715708.016681.jpg
Views: 193
Size:  70.9 KB

Also, although this is probably not the best practise for fp2, the question says 'or otherwise' which means you could do it by induction
It is different to the book, it is on the solutionbank.

(Original post by ghostwalker)
Consecutive numerators are 2,1,-3, so stick them in a table (you'll have to imagine it having more columns/rows):

\begin{matrix} 2 & 1 & -3 & & & & \\ & 2 & 1 & -3 & & \\ & & 2 & 1 & -3 & \\ & & &   2 & 1 & -3\end{matrix}

And add the colums (these correspond to the same denominator).

Everything cancels, except two terms at the start, and two at the end.
Thank you so much, will have a go when I have finished some m2 regards!

(Original post by davros)
The question the OP is tackling is contained in the pdf file attached to the original post. Strangely, it seems to be a SolutionBank with solutions to every question except the one the OP is doing!
Yeah this was the case, when I was checking my answers this question came, and I got stuck on that part.

Thanks for all your replies guys.
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