Representing pressure of a gas?
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magic_andrew
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Show that the pressure of a gas can be represented by P = (p<c>2)/3
So far I have used p = m/v and substituted it into the equation PV = 1/3Nmc2rms. So I've got P = 1/3 Npc2rms. Is the N necessary and does the rms part matter?
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lerjj
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#2
Not that relevant, but in at least some contexts <x> means average value of x. That's probably what the tags meant.
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Stonebridge
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#3
(Original post by magic_andrew)
Not sure if those tags were just a formatting error but I've included them just in case.
So far I have used p = m/v and substituted it into the equation PV = 1/3Nmc2rms. So I've got P = 1/3 Npc2rms. Is the N necessary and does the rms part matter?
Not sure if those tags were just a formatting error but I've included them just in case.
So far I have used p = m/v and substituted it into the equation PV = 1/3Nmc2rms. So I've got P = 1/3 Npc2rms. Is the N necessary and does the rms part matter?
If m is the mass of one atom then Nm is the total mass of gas.
Nm/V is density as it's mass / volume.
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Phichi
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#4
(Original post by magic_andrew)
Not sure if those tags were just a formatting error but I've included them just in case.
So far I have used p = m/v and substituted it into the equation PV = 1/3Nmc2rms. So I've got P = 1/3 Npc2rms. Is the N necessary and does the rms part matter?
Not sure if those tags were just a formatting error but I've included them just in case.
So far I have used p = m/v and substituted it into the equation PV = 1/3Nmc2rms. So I've got P = 1/3 Npc2rms. Is the N necessary and does the rms part matter?

However:


Your question was to prove:
P = (p<c>2)/3
Are you you positive it wasn't

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magic_andrew
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#5
(Original post by Phichi)
represents the mean value.
However:
, also, 
Your question was to prove:
P = (p<c>2)/3
Are you you positive it wasn't

However:


Your question was to prove:
P = (p<c>2)/3
Are you you positive it wasn't

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Dalek1099
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#6
(Original post by magic_andrew)
Yeh it's definetly outside the tags. It might just be a mistake by my lecturer so if it helps then just use the power inside the tags.
Yeh it's definetly outside the tags. It might just be a mistake by my lecturer so if it helps then just use the power inside the tags.
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magic_andrew
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#7
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