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Higher Derivatives(FP2)

Could someone possibly help with 6b? 6a is fine :smile:
Thank you! ImageUploadedByStudent Room1424722089.470667.jpg


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Original post by Ahmederno
mutley do u do physics?
if so do u know where i could find the ocr b physics june 2014 paper because I heard its a good paper to practise (i heard it was a bit challenging )


1. ask your teacher for a copy
2. please don't comment on a thread if your comment is irrelevant
3. I believe giving access to recent papers is against TSR rules
4. I don't have a copy any way


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Reply 2
sry :smile:
Reply 3
Original post by Mutleybm1996
Could someone possibly help with 6b? 6a is fine :smile:
Thank you! ImageUploadedByStudent Room1424722089.470667.jpg


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by inspection n=3 isn't it?
Reply 4
Substitute x = 2 and n = N into the equation you just proved and compare the RHS of both equations.
Original post by TeeEm
by inspection n=3 isn't it?


Yes but i don't see why
Sorry if I'm being a plonker


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Reply 6
Original post by Mutleybm1996
Yes but i don't see why
Sorry if I'm being a plonker


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happens
Reply 7
Original post by Mutleybm1996
Could someone possibly help with 6b? 6a is fine :smile:
Thank you! ImageUploadedByStudent Room1424722089.470667.jpg


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Use the fact that ln 4 = 2ln 2 and you're virtually there!
Original post by 1 8 13 20 42
Substitute x = 2 and n = N into the equation you just proved and compare the RHS of both equations.


So 4ln(2)^n = ln(4)^2 ln(2)


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Original post by davros
Use the fact that ln 4 = 2ln 2 and you're virtually there!


GOTTIT! Thanks :biggrin:


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Reply 10
Original post by Mutleybm1996
So 4ln(2)^n = ln(4)^2 ln(2)


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(ln2)n(22)=(2ln2)2ln2(ln2)^n(2^2) = (2ln2)^2ln2

Square the two out, and use (ln2)2×ln2=(ln2)3(ln2)^2\times ln2 = (ln2)^3

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