# M2 Differential Equations - Help

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#1
Hey
I can do part a however I'm not sure if my answer to part b is right could someone check for me I got

Edit: I've attached my working out below
0
5 years ago
#2
Hey
I can do part a however I'm not sure if my answer to part b is right could someone check for me I got

You will have better response if you post your workings.
Most people are relactunt to check simply because they will have to do the question themselves. (imagine someone is on a bus and could help but has no pen and paper ...)
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#3
(Original post by TeeEm)
You will have better response if you post your workings.
Most people are relactunt to check simply because they will have to do the question themselves. (imagine someone is on a bus and could help but has no pen and paper ...)
0
5 years ago
#4

1/(50-v) integrates to -ln|50-v|

also after separation it should be 1/25 dt not 25 dt
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#5
(Original post by TeeEm)

1/(50-v) integrates to -ln|50-v|

also after separation it should be 1/25 dt not 25 dt
any better ?
0
5 years ago
#6
any better ?
it is ok now

you may want to write the exponential as v= 50 -50e-0.04t
0
5 years ago
#7
Hey
I can do part a however I'm not sure if my answer to part b is right could someone check for me I got

Edit: I've attached my working out below
(50-v)/25 = dv/dt
1/(50-v)dv = 1/25dt
Integrate:
-ln|50-v| = t/25 + c
t=0 v=0
-ln|50| = c
ln|50| - ln|50-v| = 25t
50/(50-v) = et/25
50/et/25 = 50-v

Now you've rearranged and integrated, solve for v

Hope this helps
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#8
(Original post by TeeEm)
it is ok now

you may want to write the exponential as v= 50 -50e-0.04t
Alrighty thanks a bunch appreciate it
0
5 years ago
#9
Alrighty thanks a bunch appreciate it
no worries
0
#10
(Original post by HenryHiddler)
(50-v)/25 = dv/dt
1/(50-v)dv = 1/25dt
Integrate:
-ln|50-v| = t/25 + c
t=0 v=0
-ln|50| = c
ln|50| - ln|50-v| = 25t
50/(50-v) = et/25
50/et/25 = 50-v

Therefore,
v = 50 - 50/et/25

Hope this helps
I've solved it thanks for your reply though maybe you can help me with the next one as I'm sure there will be many to follow
0
5 years ago
#11
I've solved it thanks for your reply though maybe you can help me with the next one as I'm sure there will be many to follow
Sure, happy to help a fellow M2 buddy :3 PM me if you want

Hope this helps
0
5 years ago
#12
(Original post by HenryHiddler)
Sure, happy to help a fellow M2 buddy :3 PM me if you want

Hope this helps
Please don't post full solutions, it is not allowed.
0
5 years ago
#13
(Original post by Muttley79)
Please don't post full solutions, it is not allowed.
Oops sorry! Second time I've done this :P Edited it now Thank you friend

Hope this helps
0
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