RHCPfan
Badges: 12
Rep:
?
#1
Report Thread starter 5 years ago
#1
Hey,
I was ill when we had class on this so I have been left a bit stuck on this question.

Calculate the electrical potential and the electric field strength at position Z due to two charges X and Y placed in air as shown in diagram.

Name:  electricfields.jpg
Views: 222
Size:  11.2 KB

5.0m = XZ = ZY = XY

Any help is appreciated!
0
reply
Stonebridge
Badges: 13
Rep:
?
#2
Report 5 years ago
#2
(Original post by RHCPfan)
Hey,
I was ill when we had class on this so I have been left a bit stuck on this question.

Calculate the electrical potential and the electric field strength at position Z due to two charges X and Y placed in air as shown in diagram.

Name:  electricfields.jpg
Views: 222
Size:  11.2 KB

5.0m = XZ = ZY = XY

Any help is appreciated!
So that we don't waste time helping you with what you already know, can you tell us what you know.
What equations do you know for the electric potential and electric field strength at a point a distance r from a charge Q?

The value at the point Z is the sum of the two due to the two individual charges.
The potential is just the straight sum, and the field strength has to be added as vectors.
0
reply
RHCPfan
Badges: 12
Rep:
?
#3
Report Thread starter 5 years ago
#3
(Original post by Stonebridge)
So that we don't waste time helping you with what you already know, can you tell us what you know.
What equations do you know for the electric potential and electric field strength at a point a distance r from a charge Q?

The value at the point Z is the sum of the two due to the two individual charges.
The potential is just the straight sum, and the field strength has to be added as vectors.
Like I said I missed out on the teaching of all this but from what I gather electrical field strength is E = F/Q and electrical potential is E = q x Ve.

Ok having tried to find more notes online for this I now have for electric field strength

E = 1/4piE0 x Q/r^2

For XZ - E = +10muC/5.0 m x 8.854 x 10^-12

For YZ - E = -10muC/5.0 m x 8.854 x 10^-12

Eo is a constant given at 8.854 x 10^-12

Is this going in the right direction?
0
reply
Stonebridge
Badges: 13
Rep:
?
#4
Report 5 years ago
#4
(Original post by RHCPfan)

Ok having tried to find more notes online for this I now have for electric field strength

E = 1/4piE0 x Q/r^2

For XZ - E = +10muC/5.0 m x 8.854 x 10^-12

For YZ - E = -10muC/5.0 m x 8.854 x 10^-12

Eo is a constant given at 8.854 x 10^-12

Is this going in the right direction?
Yes.

That's the equation for electric field strength.
This represents a force and is a vector.

The equation for electric potential is almost the same but has r and not r2
Potential is scalar and easier to add.
I suggest you start with the potential question.
Find the potential at that point due to each charge, using the formula, and add the values, taking account of whether the value is positive or negative. (due to the sign of the charge.)
Do you have the correct answer to check it?
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

What do you want most from university virtual open days and online events?

I want to be able to watch in my own time rather than turn up live (195)
29.77%
I want to hear more about the specifics of the course (109)
16.64%
I want to be able to dip in and dip out of lots of different sessions (58)
8.85%
I want to meet current students (55)
8.4%
I want to meet academics and the people that will be teaching me (51)
7.79%
I want to have a taster lecture or workshop to see what the teaching is like (128)
19.54%
My parents/guardians are more interested than me to be honest (38)
5.8%
Other things – I'll tell you in the thread (21)
3.21%

Watched Threads

View All
Latest
My Feed