A helicopter is ascending vertically with a speed of 5.20 m/s. At a height of 125 m above the Earth, package is dropped from a window. How much time does it take for the package to reach the ground? [Hint: The package's initial speed equals the helicopter's.]
When the package is dropped, the path of the package is like this?
A helicopter is ascending vertically with a speed of 5.20 m/s. At a height of 125 m above the Earth, package is dropped from a window. How much time does it take for the package to reach the ground? [Hint: The package's initial speed equals the helicopter's.]
When the package is dropped, the path of the package is like this?
It's upward motion would decelerate in a vertical line until it stopped and then accelerate back vertically downwards along the same path.
i guess here , the initial velocity ,U=0 V=5.2 and S(displacement)=125 And t=? so you'd have to use the formula that has all these variables present ,in this case, s=ut+1/2 at^2