Hi guys, can anyone help me with the detailed steps to solving this..I mean I kinda get the gist, I just don't properly understand what I'm doing.
so this question says
A curve has the equation y= x + 1/x
Use calculus to show that the curve has a turning point at x= 1
Show also that this point is a minimum.
Okay, so firstly I began by differentiating to get
dy/dx = 1-x^-2
and I didn't know what to do from this point.....
should I make dy/dx = 0
so I end up with 1-1/x^2 = 0
then 1/x^2 = 1
then x^2 = 1
then x = sqrt1
then x = + or - 1
?
I mean, im confused. I know that i need to find d2y/dx2 to prove that its a minimum, which i did and i got 2x^-3
then i tried to sub 1 into d2y/dx2 and i got 2 which is >0 therefore its a minimum.
I just don't understand what to properly do.
The next problem says:
A curve has gradient given by dy/dx = x^2 -6x + 9
Find d2y/dx2
Show that the curve has a stationary point of inflection when x = 3
i found d2y/dx2 as 2x-6
and then I didnt know what to do here either...
I subbed x = 3 into dy/dx and d2y/dx2 and got x = 0 for both and then said it was a point of inflection as the sign doesnt change but I just don't know how to lay it out...
Can someone please help