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Titration question

Copper solution is titrated against EDTA (0.022 mol dm^3)

The copper solution is originally mixed in with nickel solution, the two are separated and the made up to 250cm^3, 50cm^3 of this solution is used for the titration. 17.3cm^3 of EDTA is used to reach the end point, calculate the concentration of copper in the solution.

I've used m = cv, m=0.022 x 17.3/1000 to get the moles of EDTA
I think its a 1:1 ratio so these moles are also the moles of copper
then used n x mr = m
and did m x 20 x 5 to get the concentration in g dm^-3 does this seem ok?

urgent please =P

**solved, my method here is wrong**

(edited 9 years ago)