Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Year 12s: what will be the first way you research your future options? >>

Clearing Algebraic Fractions Help

Im having some difficulty understanding how to do this equation an my brain is melting. I understand that I need to try and multiply out the denominators and I tried using 18.

5/(Y-3) = 8/(Y-6) Solve for Y

I don't know how to attack it should I split the numerator into 2+3 and 5+3 and cancel out the 3's or just go straight into multiplying by Y+18. If someone could give me a hint I would be forever in your debt!

You should multiply both sides by

(y-3)

and

(y-6)

so ;

\dfrac{5(y-3)(y-6)}{(y-3)}

=

\dfrac{8(y-6)(y-3)}{(y-6)}

as the

(y-3)

on the left and the

(y-6)

on the right cancel out, you're left with:

5(y-6)

=

8(y-3)

expand, simplify, solve for y.

(edited 9 years ago)

OP

Original post by edothero

You should multiply both sides by

(y-3)

and

(y-6)

so ;

\dfrac{5(y-3)(y-6)}{(y-3)}

=

\dfrac{8(y-6)(y-3)}{(y-6)}

as the

(y-3)

on the left and the

(y-6)

on the right cancel out, you're left with:

5(y-6)

=

8(y-3)

expand, simplify, solve for y.

Thank you so much. I couldn't get my head around it and thought it should be one or the other! Your the best!

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