linear graphs questionWatch

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Thread starter 4 years ago
#1
the picture is a kite with A being the point (2,9) and C which is (8,1). the first question asked to find x which is (5,5), the second part is asking to find the equation of the diagonal DB, how do I do this? please help Posted from TSR Mobile
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Thread starter 4 years ago
#2
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4 years ago
#3
(Original post by bubblegumcat)
the picture is a kite with A being the point (2,9) and C which is (8,1). the first question asked to find x which is (5,5), the second part is asking to find the equation of the diagonal DB, how do I do this? please help Posted from TSR Mobile
did you know that the diagonals of cross at right angles and does that help?
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Thread starter 4 years ago
#4
(Original post by maggiehodgson)
did you know that the diagonals of cross at right angles and does that help?
I do, do I use Pythagoras for that?

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4 years ago
#5
(Original post by bubblegumcat)
I do, do I use Pythagoras for that?

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Can you find the equation of a straight line given two points? And do you know about the gradients of perpendicular lines?
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4 years ago
#6
If you know points D and B you can use y-b=m(x-a) to work out equation
m = gradient (can be worked out from two points)
A = x coordinate of one of the points
B = y coordinate if the same point

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Thread starter 4 years ago
#7
(Original post by maggiehodgson)
Can you find the equation of a straight line given two points? And do you know about the gradients of perpendicular lines?
do i find the gradient of AC then use that to find the equation of DB, is DB perpendicular to AC?
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Thread starter 4 years ago
#8
(Original post by It's_Ailie)
If you know points D and B you can use y-b=m(x-a) to work out equation
m = gradient (can be worked out from two points)
A = x coordinate of one of the points
B = y coordinate if the same point

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i would if i knew the point of d and b but they don't give it haha, thanks though
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4 years ago
#9
(Original post by bubblegumcat)
i would if i knew the point of d and b but they don't give it haha, thanks though
Ah ah BUT you know that the diagonals cross at a point for which you have calculated the co-ordinates. And I suspect you can now use the gradient and the x and y values to find the equation of the line.

Yes? No?
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Thread starter 4 years ago
#10
(Original post by maggiehodgson)
Ah ah BUT you know that the diagonals cross at a point for which you have calculated the co-ordinates. And I suspect you can now use the gradient and the x and y values to find the equation of the line.

Yes? No?
yes? was i write about the other thing, using the gradient of AC to find the equation of perpendicular DB line?
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4 years ago
#11
(Original post by bubblegumcat)
yes? was i write about the other thing, using the gradient of AC to find the equation of perpendicular DB line?
Yes. The product of the gradients of perpendicular lines is -1 (just in case you needed a reminder)
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Thread starter 4 years ago
#12
(Original post by maggiehodgson)
Yes. The product of the gradients of perpendicular lines is -1 (just in case you needed a reminder)
thanks, i worked out the answer 0
4 years ago
#13
(Original post by bubblegumcat)
thanks, i worked out the answer Hurray. Well done.
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