username1333513
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the picture is a kite with A being the point (2,9) and C which is (8,1). the first question asked to find x which is (5,5), the second part is asking to find the equation of the diagonal DB, how do I do this? please helpName:  ImageUploadedByStudent Room1427222797.066397.jpg
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maggiehodgson
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(Original post by bubblegumcat)
the picture is a kite with A being the point (2,9) and C which is (8,1). the first question asked to find x which is (5,5), the second part is asking to find the equation of the diagonal DB, how do I do this? please helpName:  ImageUploadedByStudent Room1427222797.066397.jpg
Views: 63
Size:  113.2 KB


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did you know that the diagonals of cross at right angles and does that help?
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(Original post by maggiehodgson)
did you know that the diagonals of cross at right angles and does that help?
I do, do I use Pythagoras for that?


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(Original post by bubblegumcat)
I do, do I use Pythagoras for that?


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Can you find the equation of a straight line given two points? And do you know about the gradients of perpendicular lines?
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It's_Ailie
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If you know points D and B you can use y-b=m(x-a) to work out equation
m = gradient (can be worked out from two points)
A = x coordinate of one of the points
B = y coordinate if the same point


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(Original post by maggiehodgson)
Can you find the equation of a straight line given two points? And do you know about the gradients of perpendicular lines?
do i find the gradient of AC then use that to find the equation of DB, is DB perpendicular to AC?
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(Original post by It's_Ailie)
If you know points D and B you can use y-b=m(x-a) to work out equation
m = gradient (can be worked out from two points)
A = x coordinate of one of the points
B = y coordinate if the same point


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i would if i knew the point of d and b but they don't give it haha, thanks though
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(Original post by bubblegumcat)
i would if i knew the point of d and b but they don't give it haha, thanks though
Ah ah BUT you know that the diagonals cross at a point for which you have calculated the co-ordinates. And I suspect you can now use the gradient and the x and y values to find the equation of the line.

Yes? No?
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(Original post by maggiehodgson)
Ah ah BUT you know that the diagonals cross at a point for which you have calculated the co-ordinates. And I suspect you can now use the gradient and the x and y values to find the equation of the line.

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yes? was i write about the other thing, using the gradient of AC to find the equation of perpendicular DB line?
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(Original post by bubblegumcat)
yes? was i write about the other thing, using the gradient of AC to find the equation of perpendicular DB line?
Yes. The product of the gradients of perpendicular lines is -1 (just in case you needed a reminder)
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(Original post by maggiehodgson)
Yes. The product of the gradients of perpendicular lines is -1 (just in case you needed a reminder)
thanks, i worked out the answer
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(Original post by bubblegumcat)
thanks, i worked out the answer

Hurray. Well done.
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