Help!! Differentiation find maximum heightWatch

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Thread starter 4 years ago
#1
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4 years ago
#2
(Original post by iamspiderman)
A ball is thrown upwards. It's height at time t seconds is given by h=25t -5t^2. Find the maximum height that the ball reaches.

What do you get if you differentiate height (displacement)?

What is the ball's velocity at the maximum height?
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4 years ago
#3
(Original post by iamspiderman)
A ball is thrown upwards. It's height at time t seconds is given by h=25t -5t^2. Find the maximum height that the ball reaches.

Differentiate once.
Put equal to zero.
Sub those values into displacement formula.
Check which is furthest.
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4 years ago
#4
(Original post by Placeboo123)
Differentiate twice.
Put equal to zero.
I don't think this is right.
Acceleration at the top should be equal to 9.8.
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4 years ago
#5
(Original post by iamspiderman)
A ball is thrown upwards. It's height at time t seconds is given by h=25t -5t^2. Find the maximum height that the ball reaches.

Are you expected to use differentiation for this? You could also answer the question by completing the square
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