Imrankhan0121
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hey can you help me on these questions? they all from Pure core maths 1&2 questions. Mostly they are logs question and one series
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Imrankhan0121
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question and one series
the first pic i rerange the 1st equ to logy=5-logx
logx(5-logx)
then you get xsquared-5x+=0
but thats wrong Why[/QUOTE]
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Imrankhan0121
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the 2nd pic is why does 2=log3=2*loga +log3
the times confusing me
i know where the log(base a)a comes from because it equals 1
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Imrankhan0121
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the third pic is the circle question is confusing
my working out
x=log3^(0.5)
so
3^(0.5)=log2^(x)
then takes log both sides
you finally get
log3.5/log2=x
x=1.807
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Placeboo123
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Judging by the 'your' in the title and the bog standard c1/2 questions, you'RE not very clever.
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Imrankhan0121
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wow
then try the question
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ThatPerson
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(Original post by Imrankhan0121)
wow
then try the question
You do realise that this is a help forum....if you're stuck and post a question people will respond, but if you entitle it "help if your clever...test your self" it'll put people off answering. Also the pictures are out of focus; it's hard to make out the questions.
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Imrankhan0121
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(Original post by ThatPerson)
You do realise that this is a help forum....if you're stuck and post a question people will respond, but if you entitle it "help if your clever...test your self" it'll put people off answering. Also the pictures are out of focus; it's hard to make out the questions.
Sorry I used the title to make my thread unique
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Imrankhan0121
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U can still manage to see it
And can u change the title because I can't do it
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physicsmaths
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(Original post by Imrankhan0121)
Sorry I used the title to make my thread unique
Lol haha u joker


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TenOfThem
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(Original post by Imrankhan0121)
hey can you help me on these questions? they all from Pure core maths 1&2 questions. Mostly they are logs question and one series
Can you type out some of the questions as the pictures are unclear
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Smaug123
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(Original post by Imrankhan0121)
Sorry I used the title to make my thread unique
Make your title descriptive, not unique. Unique is fine if you have clickbait, but you're looking for help, not ad revenue.
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Kvothe the Arcane
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(Original post by Imrankhan0121)
U can still manage to see it
And can u change the title because I can't do it
Press edit of the first post. And then advanced edit and you'll be able to change the title.
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Imrankhan0121
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(Original post by keromedic)
Press edit of the first post. And then advanced edit and you'll be able to change the title.
Thanks G
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morgan8002
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(Original post by Placeboo123)
Judging by the 'your' in the title and the bog standard c1/2 questions, you'RE not very clever.
Not everyone is as good at maths as you.
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Placeboo123
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(Original post by morgan8002)
Not everyone is as good at maths as you.
Yeah and not as good in English as you
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ThatPerson
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(Original post by Imrankhan0121)
question and one series
the first pic i rerange the 1st equ to logy=5-logx
logx(5-logx)
then you get xsquared-5x+=0
but thats wrong Why
You've forgotten the 6.

(All logs in base 3)

You have  \log(x)\log(y) = 6 , so if you've got \log(y)=5-\log(x)

then  \log(x)\log(y) = 6 \implies \log(x)(5-\log(x))=6 . Then rearrange and solve the quadratic.
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Imrankhan0121
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(Original post by ThatPerson)
You've forgotten the 6.

(All logs in base 3)

You have  \log(x)\log(y) = 6 , so if you've got \log(y)=5-\log(x)

then  \log(x)\log(y) = 6 \implies \log(x)(5-\log(x))=6 . Then rearrange and solve the quadratic.
Ok
I was doing this at 2 am
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