lorimeed
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Help trying to revise functions and looking at my notes but can't understand how I've done this!

The question is find the range of h(x)=(x-2)squared -7
I got h(x) is more than or equal to -7.

Can anyone explain how to get there? :confused:
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Kevin De Bruyne
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(Original post by lorimeed)
Help trying to revise functions and looking at my notes but can't understand how I've done this!

The question is find the range of h(x)=(x-2)squared -7
I got h(x) is more than or equal to -7.

Can anyone explain how to get there? :confused:
What is the lowest value that (x-2)^2 - 7 takes?

It may help you to think about each term of the equation and the lowest value each one can take.
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Viratjandra
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(Original post by lorimeed)
Help trying to revise functions and looking at my notes but can't understand how I've done this!

The question is find the range of h(x)=(x-2)squared -7
I got h(x) is more than or equal to -7.

Can anyone explain how to get there? :confused:
The domain of the inverse of the function is the range. You can get the inverse by writing the h(x) to y and making x the subject.

You would normally need to complete the square to do that but it seems unnecessary on this case.
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