# Ionic equation for barium chloride and sulphuric acid?Watch

Announcements
#1
is it bacl2 + so4 -> baso4 + hcl
0
4 years ago
#2
I believe it is
BaCl2 + H2SO4 2- --> BaSO4 + 2HCl
Barium Chloride Charge is Nil
Sulphuric Acid Charge Is 2-
Hydrochloric Acid is a molecule so it cannot form ionic bonds.
I dont know if im right im in Y9 1
4 years ago
#3
(Original post by cardboardoranges)
is it bacl2 + so4 -> baso4 + hcl

(Original post by Tarick)
I believe it is
BaCl2 + H2SO4 2- --> BaSO4 + 2HCl
Barium Chloride Charge is Nil
Sulphuric Acid Charge Is 2-
Hydrochloric Acid is a molecule so it cannot form ionic bonds.
I dont know if im right im in Y9 The sulphate ion (SO4) has the 2- charge, not the molecule. All molecules are neutral.

As for the question, it's an ionic equation not a normal balanced equation, so we have to do things a little differently...

First write out all the reactants and products in their states:

Ba2+ (aq) + 2Cl- (aq) + 2H+ (aq) + SO4 2- (aq) --> Ba2+ (s) + SO4 2- (s) + 2H+ (aq) + 2Cl- (aq)

You need to know that BaSO4 is insoluble so the state changes from (aq) to (s).

Now you cancel out the ions that are exactly the same on each side (exactly the same means same state too).

Ba2+ (aq) + 2Cl- (aq) + 2H+ (aq) + SO4 2- (aq) --> Ba2+ (s) + SO4 2- (s) + 2H+ (aq) + 2Cl- (aq)

To finish off, write BaSO4 as a molecule because it doesn't dissociate into separate ions (since it's a solid):

Ba2+ (aq) + SO4 2- (aq) ---> BaSO4 (s) 1
#4
(Original post by Dylann)
The sulphate ion (SO4) has the 2- charge, not the molecule. All molecules are neutral.

As for the question, it's an ionic equation not a normal balanced equation, so we have to do things a little differently...

First write out all the reactants and products in their states:

Ba2+ (aq) + 2Cl- (aq) + 2H+ (aq) + SO4 2- (aq) --> Ba2+ (s) + SO4 2- (s) + 2H+ (aq) + 2Cl- (aq)

You need to know that BaSO4 is insoluble so the state changes from (aq) to (s).

Now you cancel out the ions that are exactly the same on each side (exactly the same means same state too).

Ba2+ (aq) + 2Cl- (aq) + 2H+ (aq) + SO4 2- (aq) --> Ba2+ (s) + SO4 2- (s) + 2H+ (aq) + 2Cl- (aq)

To finish off, write BaSO4 as a molecule because it doesn't dissociate into separate ions (since it's a solid):

Ba2+ (aq) + SO4 2- (aq) ---> BaSO4 (s) Thabks so much.
0
9 months ago
#5
(Original post by dylann)
the sulphate ion (so4) has the 2- charge, not the molecule. All molecules are neutral.

As for the question, it's an ionic equation not a normal balanced equation, so we have to do things a little differently...

First write out all the reactants and products in their states:

Ba2+ (aq) + 2cl- (aq) + 2h+ (aq) + so4 2- (aq) --> ba2+ (s) + so4 2- (s) + 2h+ (aq) + 2cl- (aq)

you need to know that baso4 is insoluble so the state changes from (aq) to (s).

Now you cancel out the ions that are exactly the same on each side (exactly the same means same state too).

Ba2+ (aq) + 2cl- (aq) + 2h+ (aq) + so4 2- (aq) --> ba2+ (s) + so4 2- (s) + 2h+ (aq) + 2cl- (aq)

to finish off, write baso4 as a molecule because it doesn't dissociate into separate ions (since it's a solid):

Ba2+ (aq) + so4 2- (aq) ---> baso4 (s)

:d
0
X

new posts Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• University of Hertfordshire
Sat, 16 Nov '19
• University of Roehampton
Sat, 16 Nov '19
• Swansea University
Sat, 16 Nov '19

### Poll

Join the discussion

#### Which party will you be voting for in the General Election?

Conservatives (58)
18.77%
Labour (124)
40.13%
Liberal Democrats (62)
20.06%
Green Party (23)
7.44%
Brexit Party (9)
2.91%
Independent Group for Change (Change UK) (0)
0%
SNP (4)
1.29%
Plaid Cymru (5)
1.62%
Democratic Unionist Party (DUP) (0)
0%
Sinn Fein (0)
0%
SDLP (0)
0%
Ulster Unionist (0)
0%
UKIP (3)
0.97%
Other (3)
0.97%
None (18)
5.83%