# Proof by induction beastWatch

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#1
https://644625398389466aee0063322305...0NRNU0/CH6.pdf

Exercise 6A Question 10

I get stuck after assuming true after n=k.

I have no idea what that solution is representing.

Can anyone help pls.

Thanks!
0
4 years ago
#2
(Original post by Damien_Dalgaard)
https://644625398389466aee0063322305...0NRNU0/CH6.pdf

Exercise 6A Question 10

I get stuck after assuming true after n=k.

I have no idea what that solution is representing.

Can anyone help pls.

Thanks!
The link you have given has complete worked solutions so what is the problem?
0
#3
(Original post by brianeverit)
The link you have given has complete worked solutions so what is the problem?
The series starts with n as 2n, I haven't done anything like this before.

I don't understand what to do for these.
0
4 years ago
#4
(Original post by Damien_Dalgaard)
The series starts with n as 2n, I haven't done anything like this before.

I don't understand what to do for these.
Do you mean Exercise A questiuon 10, if so the series is from r=1 to r=2n so I don't understand what you are saying about it starting with n as 2n.
0
#5
(Original post by brianeverit)
Do you mean Exercise A questiuon 10, if so the series is from r=1 to r=2n so I don't understand what you are saying about it starting with n as 2n.
Generally in the excerise book and in past papers these specific questions are from r=n to r=1.

My question is does something else need to be done when it is from r=2n to r=n.
0
4 years ago
#6
(Original post by Damien_Dalgaard)
Generally in the excerise book and in past papers these specific questions are from r=n to r=1.

My question is does something else need to be done when it is from r=2n to r=n.
the sum from r=n to r=2n is the sum from r=1 to r=2n minus the sum from r=1 to r=n-1.
1
#7
(Original post by Goods)
the sum from r=n to r=2n is the sum from r=1 to r=2n minus the sum from r=1 to r=n-1.

THank you.
0
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