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Confidence Intervals probability

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(edited 4 years ago)
Original post by douglas merritte

I don't understand how e) and g) have been calculated. Any help on this is much appreciated!


Conditional probability.

Let C95 be the event μ\mu is in the 95% C.I. And we know P(C95) = 0.95.
Similarly C99.
Note also that C95 is a subset of C99.

Then for e)
We want P(C99|¬C95), using "¬" to denote the complementary event.

By conditional probability this equals P(C99&¬C95)/P(¬C95)

=P(C99)P(C95)1P(C95)=\frac{P(C99)-P(C95)}{1-P(C95)} since C95 is a subset of C99.

=0.990.9510.95=0.8=\frac{0.99-0.95}{1-0.95}=0.8

Can you have a go at g) now youself?
(edited 9 years ago)

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