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FP2 First Order Differential Graphs

For the questions in which you are required to sketch a graph, how is this meant to be done?


On Solution Bank it just shows it as sketching the graph with no working out whatsoever, but even for the question shown, surely I'm not meant to know how to plot a y=x2+16+cy=\sqrt{x^{2}+16}+c graph.
So how would I go about doing this, simple do a plot of all the points for each x coordinate?
(edited 8 years ago)
Reply 1
Original post by Jimmy_M
For the questions in which you are required to sketch a graph, how is this meant to be done?


On Solution Bank it just shows it as sketching the graph with no working out whatsoever, but even for the question shown, surely I'm not meant to know how to plot a y=x2+16+cy=\sqrt{x^{2}+16}+c graph.
So how would I go about doing this, simple do a plot of all the points for each x coordinate?


with standard curve sketching techniques
Reply 2
Original post by TeeEm
with standard curve sketching techniques

Care to explain? I've never been taught any "techniques" for graph sketching..
Reply 3
Original post by Jimmy_M
Care to explain? I've never been taught any "techniques" for graph sketching..


general shape
x and y intercepts
stationary points
any asymptotic behaviour
any symmetries inc odd and even
etc

EDEXCEL never really tests this so I would not worry about this too much.

If you want to look at some examples look at this link
http://madasmaths.com/archive/maths_booklets/further_topics/various/curve_sketching.pdf
Reply 4
Original post by TeeEm
general shape
x and y intercepts
stationary points
any asymptotic behaviour
any symmetries inc odd and even
etc

EDEXCEL never really tests this so I would not worry about this too much.

If you want to look at some examples look at this link
http://madasmaths.com/archive/maths_booklets/further_topics/various/curve_sketching.pdf

Thank you very much :smile:
Reply 5
Original post by Jimmy_M
Thank you very much :smile:


my pleasure
Reply 6
square root of X^2+16 is simply X+4. It is just a translation of Y=X.

or you could work out the co-ords by saying 'when Y=0, X must be -4'. 'also when X=0, Y must be 4.' That'll give you two co-ords to plot and draw a line between (which is all they require as its just a SKETCH not drawing)

(hope this made sense!)


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Reply 7
Original post by hafiza.irshad
square root of X^2+16 is simply X+4. It is just a translation of Y=X.

Posted from TSR Mobile


No it isn't!

(X+4)^2 = X^2 + 8X + 16

You can't simplify the square root of X^2 + 16
Original post by TeeEm
general shape
x and y intercepts
stationary points
any asymptotic behaviour
any symmetries inc odd and even
etc

EDEXCEL never really tests this so I would not worry about this too much.

If you want to look at some examples look at this link
http://madasmaths.com/archive/maths_booklets/further_topics/various/curve_sketching.pdf

Just had a look at your link. Very good stuff. Thanks for providing :biggrin:.

Will attempt some stuff later. Graph sketching is not my strong suit. The stuff beyond the simple examples in the books.
(edited 8 years ago)
Original post by hafiza.irshad
square root of X^2+16 is simply X+4. It is just a translation of Y=X.

or you could work out the co-ords by saying 'when Y=0, X must be -4'. 'also when X=0, Y must be 4.' That'll give you two co-ords to plot and draw a line between (which is all they require as its just a SKETCH not drawing)

(hope this made sense!)


Posted from TSR Mobile


Lol no its not.


Posted from TSR Mobile
Reply 10
Original post by keromedic
Just had a look at your link. Very good stuff. Thanks for providing :biggrin:.

Will attempt some stuff later. Graph sketching is not my strong suit. The stuff beyond the simple examples in the books.


my pleasure

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