# AQA - Physics - Help on a decay question!!!

Thread starter 7 years ago
#1
The pie + mesons at rest decay into muons which are always emitted at a certain speed. The equation below represents the decay of a Pie + meson into a positive muon and another particle "Y", which is an muon neutrino.
http://prntscr.com/6wj6xi <---- this is the equation!

Ok so I was wondering why it is not a regular neutrino and also a pie meson + has a lepton number of 0 and a muon+ has a lepton number of 1 and the muon neutrino also has a lepton number of +1, how is it that this decay is possible; isn't lepton number always conserved?
0
7 years ago
#2
The lepton number conservation law is specific between types of leptons. So they will teach you that "lepton number is conserved" where in truth the lepton muon number is conserved, the lepton electron number is conserved, etc

and a muon+ should have a muon lepton number of -1
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