Kirchhoff's first lawWatch

Announcements
Thread starter 4 years ago
#1
To calculate the charge, we use Q=It. But from the diagram how do I know the value of the current pass through a given point?
0
4 years ago
#2
(Original post by TammyChong)
To calculate the charge, we use Q=It. But from the diagram how do I know the value of the current pass through a given point?
Heya, I'm going to put this in the physics forum for you as you should get more responses there.

You should also check out the forum to see if there's any other threads there which might be helpful to you!

http://www.thestudentroom.co.uk/forumdisplay.php?f=372
0
4 years ago
#3
(Original post by TammyChong)
To calculate the charge, we use Q=It. But from the diagram how do I know the value of the current pass through a given point?
Is it d or have I made a mistake?

Posted from TSR Mobile
0
4 years ago
#4
(Original post by TammyChong)
To calculate the charge, we use Q=It. But from the diagram how do I know the value of the current pass through a given point?
Well you have 2 branches all you need to do is use kirckhoff 1 to make the currents add.
0
4 years ago
#5
whats the answer? you can work back from there to find current for the purpose of understanding how to get it.
0
4 years ago
#6
I would have said D too, 3A enter, 1A heads down one branch whilst the other 2A head towards R.

So the calculation using Q=IT would be Q=2×5 remembering I is measured in amps and T is measured in seconds.

2×5 = 10. Q=10. Answer is D! Posted from TSR Mobile
0
4 years ago
#7
Am I reading this wrong but Im looking at as if 1A is approaching a junction and then splits - except 3A spontaneously appears from nowhere.

Ohh wait I think we assume that The 3A is the current when the junctions come to a point, so the arrow on R would be pointing left and upwards. so the R + 1A = 3A therefore R = 2A

Does this make sense ?
0
4 years ago
#8
(Original post by Walex12108)
Am I reading this wrong but Im looking at as if 1A is approaching a junction and then splits - except 3A spontaneously appears from nowhere.

Ohh wait I think we assume that The 3A is the current when the junctions come to a point, so the arrow on R would be pointing left and upwards. so the R + 1A = 3A therefore R = 2A

Does this make sense ?
The second paragraph is exactly it! 1+2=3! Arrow pointing NW Posted from TSR Mobile
0
X

new posts Back
to top
Latest
My Feed

Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

University open days

• University of Bristol
Wed, 23 Oct '19
• University of Exeter
Undergraduate Open Day - Penryn Campus Undergraduate
Wed, 23 Oct '19
• University of Nottingham
Mini Open Day Undergraduate
Wed, 23 Oct '19

Poll

Join the discussion

Have you made up your mind on your five uni choices?

Yes I know where I'm applying (116)
66.29%
No I haven't decided yet (35)
20%
Yes but I might change my mind (24)
13.71%