username1533709
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I'm not sure how I would approach question ii and iii.
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Dalek1099
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(Original post by Kadak)
I'm not sure how I would approach question ii and iii.
you need to account for all the possibilities that y+z=3 and y*z is even a good tree diagram would be a good idea-the probabilities are independent so just multiply and look at which ones give y+z=3 and y*z=even.
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(Original post by Dalek1099)
you need to account for all the possibilities that y+z=3 and y*z is even a good tree diagram would be a good idea-the probabilities are independent so just multiply and look at which ones give y+z=3 and y*z=even.


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My attempt so far, I'm so.confused how this tree diagram would look like.
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Dalek1099
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(Original post by Kadak)
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My attempt so far, I'm so.confused how this tree diagram would look like.
There are three possibilities for both variables so you need a tree diagram with three branches(accounting for the possibilities of one variable) with three branches coming off each branch(accounting for the possibilities of the other variable as there three possibilities for the second variable for each possibility of the first variable).
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