Capacitor discharge through resistors

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Soffie
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Hi, I was wondering if someone help me with this circuit...

1. It consists of 2 capacitors and 2 resistors in a network as shown below. The idea is to disconnect battery from 1st capacitor, connect 1st capacitor to the 2nd half of circuit so that C1 discharges through the resistors and, presumably, C2 begins to charge up.

Image

Voltage graph shows the p.d. across resistor 2 which at the moment is 0 as C2 has been completely discharged.

2. I connect C1 to the circuit and get an oddly shaped graph. The p.d. across R2 rises, and then falls, exponentially back to 0. (Sorry this isn't v. clear on the graph but if you look closely you will see it does this)

Image

So basically I dont understand why the graph does this. If you connected the voltmeter across R1, you get a smooth exponential decrease curve. Is there anyone who can explain this to me?

I don't really have a straight question; I just want to know what's happening during this discharge process.

Thanks
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TSR Jessica
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Sorry you've not had any responses about this. Are you sure you’ve posted in the right place? Posting in the specific Study Help forum should help get responses.

I'm going to quote in Puddles the Monkey now so she can move your thread to the right place if it's needed. :yy:

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uberteknik
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(Original post by Soffie)
Hi, I was wondering if someone help me with this circuit...

1. It consists of 2 capacitors and 2 resistors in a network as shown below. The idea is to disconnect battery from 1st capacitor, connect 1st capacitor to the 2nd half of circuit so that C1 discharges through the resistors and, presumably, C2 begins to charge up.

Image

Voltage graph shows the p.d. across resistor 2 which at the moment is 0 as C2 has been completely discharged.

2. I connect C1 to the circuit and get an oddly shaped graph. The p.d. across R2 rises, and then falls, exponentially back to 0. (Sorry this isn't v. clear on the graph but if you look closely you will see it does this)

Image

So basically I dont understand why the graph does this. If you connected the voltmeter across R1, you get a smooth exponential decrease curve. Is there anyone who can explain this to me?

I don't really have a straight question; I just want to know what's happening during this discharge process.

Thanks
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Is it part of an ISA or EMPA?
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Soffie
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(Original post by uberteknik)
Where did this question come from?

Is it part of an ISA or EMPA?
Uh oh I think this thread should be deleted ASAP... I'm really sorry I didn't notice it was breaching the guidelines. Please delete this !!!!!!!!!!!!!!
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