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What if a resistor is placed between the E and galvanometer (effect to the balance point)?
My guess is that it will be shifted to A? or maybe stays constant. I am stuck here. Your help would be highly appreciated.
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It doesn't change the balance point, because at balance there is no current in G and therefore no pd across the resistor placed there.
What it does do is reduce the current in G when off-balance, hence helping to protect G (which is normally very sensitive) against excessive currents when you are trying to find the balance point.
What it does do is reduce the current in G when off-balance, hence helping to protect G (which is normally very sensitive) against excessive currents when you are trying to find the balance point.
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(Original post by Stonebridge)
It doesn't change the balance point, because at balance there is no current in G and therefore no pd across the resistor placed there.
What it does do is reduce the current in G when off-balance, hence helping to protect G (which is normally very sensitive) against excessive currents when you are trying to find the balance point.
It doesn't change the balance point, because at balance there is no current in G and therefore no pd across the resistor placed there.
What it does do is reduce the current in G when off-balance, hence helping to protect G (which is normally very sensitive) against excessive currents when you are trying to find the balance point.
Well, I'll try to write about how I "see" the situation which leads to V= 0 volt across. The slider with the unknown pd cell will show its max voltage at every point (lets say we can measure its voltage), but for the actual power supply, as we are varying L, so does its voltage across that points.
When both of the pd from cell and power supply are equal, electrons doesn't flow anymore, as pd = 0 V
Please go through my basic concepts and correct/add if you can. I believe understanding the real concept is the most important before solving any problem.
Thanks a ton!
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