heat of vaporization
(i) The vapour pressure of H2O is0.026 bar at 20oC and 1.01 bar at 100oC. Estimate theheat of vaporization of the liquid.
For this I am using he clapeyron equation
0.026 bar = 2600 Pa
1.01 bar = 10100 Pa
20 degrees = 293.15K
100 degrees = 373.15K
R = 8.31447
ln(P2/P1) = H/R * ( 1/T(1) - 1/T(2)
=> H = (ln(P2/P2) * R) / (1/T(1) - 1/T(2))
Putting in the values i'm not getting the right number... am I using the correct equation? rearranging incorrectly? I'm not sure...
For this I am using he clapeyron equation
0.026 bar = 2600 Pa
1.01 bar = 10100 Pa
20 degrees = 293.15K
100 degrees = 373.15K
R = 8.31447
ln(P2/P1) = H/R * ( 1/T(1) - 1/T(2)
=> H = (ln(P2/P2) * R) / (1/T(1) - 1/T(2))
Putting in the values i'm not getting the right number... am I using the correct equation? rearranging incorrectly? I'm not sure...
What number are you getting then?
Original post by Infraspecies
What number are you getting then?
10057 Pa
Original post by jacksonmeg
10057 Pa
For a heat of vaporisation?
Original post by Infraspecies
For a heat of vaporisation?
oh ive figured out where im going wrong
thanks anywayQuick Reply
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