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# As-level past paper question : factorising with negative quadratic watch

1. So hello..
it's a question from jan 2011 C1 AQA

so basically
I got 18 + 6x - 18x^2
I divided by 6

so I have
-2x^2 + x + 3

so then I got
-( (2x-3) (x+1)

but I'm confused to find x and if I did it the right method?
I get that x is 3/2 and -1 but I think it's wrong
thank you sorry it's equal to 0
2. it must equal something for you to find x
e.g.-2x^2 + x + 3 = 0

In which case just put the neg on the other side 0 = 2x^2 -x -3
3. Also 18x^2 divided by 6 is 3x^2
4. Just bring it to the other side so it isn't negative anymore

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Updated: May 9, 2015
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