Join TSR now and get all your revision questions answeredSign up now

Deducing the axis of a graph if given equation is gradient Watch

    • Thread Starter
    Offline

    0
    ReputationRep:
    Hello everyone,
    So I've been given an equation Y=1/2gpr(h+r/3)
    ive been trying to rearrange it in order to allow me to get the gradient of a graph as Y but to no avail. I tried putting the equation squared on the y axis and the equation on the x axis and they therefore will cancel (if I'm right) but that seems wrong.
    thanks a lot, any help would be greatly appreciated
    • Thread Starter
    Offline

    0
    ReputationRep:
    Bump
    • Thread Starter
    Offline

    0
    ReputationRep:
    Bumb
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    Hello everyone,
    So I've been given an equation Y=1/2gpr(h+r/3)
    ive been trying to rearrange it in order to allow me to get the gradient of a graph as Y but to no avail. I tried putting the equation squared on the y axis and the equation on the x axis and they therefore will cancel (if I'm right) but that seems wrong.
    thanks a lot, any help would be greatly appreciated
    Right, OK. This seems fun. Is it just the equation of a line or does it bear any relevance?
    • Thread Starter
    Offline

    0
    ReputationRep:
    It was a physics question but we were basically told that there were no unknowns in the questions I.e nothing is missing. I didn't actually get given any values its just a theoretical thing so the y axis divided by the x axis must equal y which is given by that equation. It seemed stupid to me given the fact that there are no unknowns... Any help would be greatly appreciated
    • Thread Starter
    Offline

    0
    ReputationRep:
    It's Y= one half (GPR) TIMES (h+ one third R) I'm not sure how to write it down propery on the web
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    It was a physics question but we were basically told that there were no unknowns in the questions I.e nothing is missing. I didn't actually get given any values its just a theoretical thing so the y axis divided by the x axis must equal y which is given by that equation. It seemed stupid to me given the fact that there are no unknowns... Any help would be greatly appreciated
    Right.

    Y=\frac{1}{2gpr(h+\frac{r}{3})}



or



Y=\frac{1}{2} gpr(h+\frac{r}{3})?
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    It's Y= one half (GPR) TIMES (h+ one third R) I'm not sure how to write it down propery on the web
    Ahhh so

    Y=\frac{h+\frac{r}{3}}{2GPR}?
    • Thread Starter
    Offline

    0
    ReputationRep:
    Hopefully this helps
    Attached Images
     
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Andy98)
    Ahhh so

    Y=\frac{h+\frac{r}{3}}{2GPR}?
    im not sure how to go about doing it
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    im not sure how to go about doing it
    How do you find the gradient of a line?
    • Thread Starter
    Offline

    0
    ReputationRep:
    Y/X, so would equation squared on y and equation on x work?
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Andy98)
    How do you find the gradient of a line?
    Y/X, so would equation squared on y and equation on x work?
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    Y/X, so would equation squared on y and equation on x work?
    In theory - however just take a look at the equation I posted for a minute - what do you notice about it?
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Andy98)
    In theory - however just take a look at the equation I posted for a minute - what do you notice about it?
    It's double y? Sorry I'm not very good at maths so I'm probably missing something obvious
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    It's double y? Sorry I'm not very good at maths so I'm probably missing something obvious
    Well from what you said your equation is a half of GPR, which is then multiplied by h+r/3, correct?
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Andy98)
    Well from what you said your equation is a half of GPR, which is then multiplied by h+r/3, correct?
    Absolutely correct
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    If I've done it right that can be represented by the equation I gave

    (Original post by EpsilonJames)
    Absolutely correct
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Andy98)
    Ahhh so

    Y=\frac{h+\frac{r}{3}}{2GPR}?
    Thank you +rep
    • Study Helper
    • Welcome Squad
    Offline

    3
    ReputationRep:
    (Original post by EpsilonJames)
    Thank you +rep
    I can't guarantee it's correct but it's what I'd use
 
 
 
Poll
How are you feeling about GCSE Results Day?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.