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    Hi gus!
    I'll explain the question.
    somebody please explain the answer! 😀
    so, there is a solution N which is aqueous sodium hydroxide.
    they divide the solution into portions, and to one of the portions they first add few drops of aqueous zinc sulfate and shake the mixture.
    next they add EXCESS aqueous zinc sulfate and shake the mixture.
    WHAT SHOULD THE OBSERVATIONS BE?
    Thank you in advance! ^_^
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    In case 1,NaOH is excess,so Zn(OH)2 will re-dissolve in NaOH,colourless Na2Zn(OH)4(aq) formed.
    In case 2,since ZnSO4 is excess,therefore,Zn(OH)2 which is white ppt. formed in the test tube.
    hope my answer is correct.
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    (Original post by piu123445)
    In case 1,NaOH is excess,so Zn(OH)2 will re-dissolve in NaOH,colourless Na2Zn(OH)4(aq) formed.
    In case 2,since ZnSO4 is excess,therefore,Zn(OH)2 which is white ppt. formed in the test tube.
    hope my answer is correct.
    thankyou so much i had been waiting for an answer since morning.... finally got one! ^_^
    I'm sure your answer is right!
    Thanks!
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    (Original post by O/LSHAMINI)
    thankyou so much i had been waiting for an answer since morning.... finally got one! ^_^
    I'm sure your answer is right!
    Thanks!
    You're welcome
    btw,what paper did you do?
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    (Original post by piu123445)
    You're welcome
    btw,what paper did you do?
    this paper was winter, 2014, paper 63 (0620) ... r u also doing the 0620 syllabus?
 
 
 
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