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    Probably me being stupid but what's the best way to go about intergration  (\ln x)^{2}

    I thought it would be just  \frac{1}{3 \times \frac{1}{x}} \times (\ln x)^{3} + C

    Thanks for your help!
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    Integration by parts.

    integral u.d/dv =uv - integral d/du.v ( . is multiplication).

    take U as (lnx)^2
    take V as X

    Where did you get this question from?
    Seems a bit hard for normal C4. Are you edexcel?
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    I think that you have to use the uv rule of integration because you can't integrate lnx directly. Then you have to use the lnx integration as v and place that in the formula. That's a really hard question though.
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    (Original post by ThatGuyRik)
    Integration by parts.

    integral u.d/dv =uv - integral d/du.v ( . is multiplication).

    take U as (lnx)^2
    take V as X

    Where did you get this question from?
    Seems a bit hard for normal C4. Are you edexcel?
    (Original post by Maannashon)
    I think that you have to use the uv rule of integration because you can't integrate lnx directly. Then you have to use the lnx integration as v and place that in the formula. That's a really hard question though.
    Yeah I think it must be by parts, frustrating that I tried to take an easy route and it didn't work. It's an OCR question 9/9 so probably why it's quite tough.

    Thanks for your help
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    (Original post by Substitution)
    Yeah I think it must be by parts, frustrating that I tried to take an easy route and it didn't work. It's an OCR question 9/9 so probably why it's quite tough.

    Thanks for your help
    Ahh i see. Yeah its cause i'm doing edexcel, haven't really come across that question in either normal or solomon papers. I was just like what the.
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    by parts ftw

    u = lnx

    dv/dx = lnx

    do they expect you to remember ∫ lnx ?
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    (Original post by the bear)
    by parts ftw

    u = lnx

    dv/dx = lnx

    do they expect you to remember ∫ lnx ?
    integrating lnx has to be done by parts aswell rofl
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    Yeah though I wouldn't put it past edexcel to have a similar question in this year's paper (hope not).
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    (Original post by ThatGuyRik)
    integrating lnx has to be done by parts aswell rofl
    you get

    xlnx -x

    ( + c )
 
 
 
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