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    (Original post by Dudeycon)
    2+2root11 / 5 or 4+4root11 / 10
    Yes same! It didn't want us to sub it into the expression for the length did it? It just wanted what x is?


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    (Original post by jpetersgill)
    Yes same! It didn't want us to sub it into the expression for the length did it? It just wanted what x is?


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    It just wanted x.
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    Anyone remember the binomial expansion question? (?x-?)^4
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    (Original post by sakuraton)
    Anyone remember the binomial expansion question? (?x-?)^4
    (3x-2)^4


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    (Original post by sakuraton)
    Anyone remember the binomial expansion question? (?x-?)^4
    (3x-2)
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    Ugh got te triangle wrong then I got something with 176 in it I think woops.

    Maybe I should try and improve at C2 then to make up for this xD
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    (Original post by DOPECYCLIST)
    probs i cant remember everything bro. i know i got it right because i got 5 for the last question which was right i know that.

    im mid way through my markscheme i will be about 30 minutes guys
    Can you include how many marks each question was worth? Thanks. Also I put min point as (-2,9) because I forgot to multiply by 3. Do you know how many marks this would lose 😁
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    (Original post by Manexopi)
    Ugh got te triangle wrong then I got something with 176 in it I think woops.

    Maybe I should try and improve at C2 then to make up for this xD
    THATS RIGHT, the answers in this thread are just simplified.
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    (Original post by Manexopi)
    Ugh got te triangle wrong then I got something with 176 in it I think woops.

    Maybe I should try and improve at C2 then to make up for this xD
    If you did the quadratic formula you got rt176 which cancels to 4rt11
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    (Original post by Manexopi)
    Ugh got te triangle wrong then I got something with 176 in it I think woops.

    Maybe I should try and improve at C2 then to make up for this xD
    This is probably right, if you got (4+sqrt(176))/10 this is correct


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    (Original post by Velocity_)
    i need help, question 7 on the june 2012 paper. How do you do this? i used the quadratic formula but obviously found the points it intercepts the x axis.... this is the only question i got wrote. thanks
    Name:  q7.gif
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    If this is the question you are on about. It's pretty simple. Simplify the equation if you want.

    a) Use F'(X) and substitute in x (4) to find the gradient of said point which is parallel to the tangent in which you substitute that gradient into y=mx+c. Then use (4,-1) as Y and X to find C. The rearrange it to make it ax+by+c=0.

    b) Well... just integrate it, then use the points to find c...
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    81x^4 - 216x^3 + 216x^2 -96x +16 I think was the binomial
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    I got that aswell.
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    (Original post by Dudeycon)
    THATS RIGHT, the answers in this thread are just simplified.
    Really?
    Because I tried simplifying and it didn't work lol
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    I am guessing you guys done the paper. I oddly found 1b) and the last question to be the hardest. Bloody surds and coordinate geometry. However, found most of the paper relitively easy betting I lost around 4 marks on 1b and 10 from q10. Assuming I got no method marks.
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    (Original post by Dudeycon)
    THATS RIGHT, the answers in this thread are just simplified.
    manexopi is right 176 was inside the squared root bit.
    #almost done will post after my history exam
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    On the earlier question of (25/9)^-1/2 I only put 3/5 instead of + or -
    I'll probably lose a mark won't I
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    (Original post by jpetersgill)
    By that you mean k>14/3 ? That's what I got


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    k<-14/3
    When you switch the minus you have to switch the sign so > becomes <
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    (Original post by jpetersgill)
    This is probably right, if you got (4+sqrt(176))/10 this is correct


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    Oh phew yeah that's what I got
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    (Original post by Rik21)
    k<-14/3
    When you switch the minus you have to switch the sign so > becomes <
    Wtf I didn't get that lol I got k>14/3


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