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    hey could anyone help me with this??

    Images:maths uni.pngName:  Screen Shot 2015-05-11 at 17.06.31.png
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    Post the math question?
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    (Original post by Marshall Taylor)
    Post the math question?
    im trying god its hard first time posting an image ;'D
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    Still can't see it? Would it be possible to write out?
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    (Original post by footchemllab)
    Still can't see it? Would it be possible to write out?
    ive done it now
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    (Original post by Marshall Taylor)
    Post the math question?
    Here ya go XD
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    i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(
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    I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

    Sorry if that's not much help!
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    Then from there, we use Euler's formula as illustrated in this link http://www.mathsisfun.com/algebra/eulers-formula.html

    We can then convert 1/4 + (rt3)/4 i into polar coordinaties, like re^io

    So r would be rt( (1/4)^2 + ((rt3)/4)^2) which is 1/2.

    Theta is tan^-1( rt3/4)/(1/4) which is exactly 60 degrees, so in radians is 1/3 pi radians.

    So it would be 1/2 e^1/3 *pi*theta
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    (Original post by gandanmo2)
    i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(
    Just realised I didn't quote you , does my explanation look right/make sense?
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    (Original post by footchemllab)
    I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

    Sorry if that's not much help!
    im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

    why would you times it by (1+i(rt3))/(1+i(rt3)??
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    (Original post by gandanmo2)
    im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

    why would you times it by (1+i(rt3))/(1+i(rt3)??
    No problem

    Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.
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    (Original post by gandanmo2)
    im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

    why would you times it by (1+i(rt3))/(1+i(rt3)??
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    (Original post by footchemllab)
    No problem

    Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.
    would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?
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    (Original post by gandanmo2)
    would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?
    Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing
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    (Original post by footchemllab)
    Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing
    Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2)
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    (Original post by gandanmo2)
    Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2)
    No problem I can't see a part B though?
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    (Original post by footchemllab)
    No problem I can't see a part B though?
    crap. my bad i meant part 2
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    (Original post by gandanmo2)
    crap. my bad i meant part 2
    I'm not a fan of proofs so this video can explain it better than me

    https://www.youtube.com/watch?v=oNKfW8Am36M
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    (Original post by footchemllab)
    I'm not a fan of proofs so this video can explain it better than me

    https://www.youtube.com/watch?v=oNKfW8Am36M
    thanks so much
    honestly means alot!
 
 
 
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