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# help needed with math question watch

1. hey could anyone help me with this??

Images:maths uni.png
2. Post the math question?
3. (Original post by Marshall Taylor)
Post the math question?
im trying god its hard first time posting an image ;'D
4. Still can't see it? Would it be possible to write out?
5. (Original post by footchemllab)
Still can't see it? Would it be possible to write out?
ive done it now
6. (Original post by Marshall Taylor)
Post the math question?
Here ya go XD
7. i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(
8. I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

Sorry if that's not much help!
9. Then from there, we use Euler's formula as illustrated in this link http://www.mathsisfun.com/algebra/eulers-formula.html

We can then convert 1/4 + (rt3)/4 i into polar coordinaties, like re^io

So r would be rt( (1/4)^2 + ((rt3)/4)^2) which is 1/2.

Theta is tan^-1( rt3/4)/(1/4) which is exactly 60 degrees, so in radians is 1/3 pi radians.

So it would be 1/2 e^1/3 *pi*theta
10. (Original post by gandanmo2)
i know its complex numbers but still i cant figure it out haha ive been out of the maths game for a year.. :'(
Just realised I didn't quote you , does my explanation look right/make sense?
11. (Original post by footchemllab)
I didn't do maths at uni so I might be wrong! For the first part, can't you multiply it by (1+i(rt3))/(1+i(rt3)) to get 1/4 + ((rt3)/4)i

Sorry if that's not much help!
im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??
12. (Original post by gandanmo2)
im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??
No problem

Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.
13. (Original post by gandanmo2)
im sucha numpty i just refreshed the page i thought this was twitter automatically refreshing

why would you times it by (1+i(rt3))/(1+i(rt3)??
14. (Original post by footchemllab)
No problem

Basically, it allows us to remove the imaginary number from the denominator. We're effectively multiplying by 1 but making our equation more simplistic in doing so, allowing us to put it in the form required.
would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?
15. (Original post by gandanmo2)
would (1+i(rt3)) x the denominator (1-i(rt3)) and cancelling out to give us 1+ i^2 root3?
Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing
16. (Original post by footchemllab)
Can you see the pic I attached above? I wrote it down on there, if you can read my pretty appalling writing
Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2)
17. (Original post by gandanmo2)
Oh got it! yeah you utter badass! thanks bro! any help with part B (not A2)
No problem I can't see a part B though?
18. (Original post by footchemllab)
No problem I can't see a part B though?
crap. my bad i meant part 2
19. (Original post by gandanmo2)
crap. my bad i meant part 2
I'm not a fan of proofs so this video can explain it better than me

20. (Original post by footchemllab)
I'm not a fan of proofs so this video can explain it better than me

thanks so much
honestly means alot!

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