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If 17x - b = 4ax + 9x - 3a for all real values of x then,

A) a = -2, b = 6
B) a = -2, b = -6
C) a = 2, b = 6
D) a = 8, b = -24
2. (Original post by flyingpanda786)

If 17x - b = 4ax + 9x - 3a for all real values of x then,

A) a = -2, b = 6
B) a = -2, b = -6
C) a = 2, b = 6
D) a = 8, b = -24
There's an easy but long way to do this, which is to substitute each of the choices and see which works (I don't necessarily recommend that, however think about exam technique - if you're stuck on a multiple choice question like this in an exam, the easiest way to get the mark is to just work out which option works and move on).
3. (Original post by flyingpanda786)

If 17x - b = 4ax + 9x - 3a for all real values of x then,

A) a = -2, b = 6
B) a = -2, b = -6
C) a = 2, b = 6
D) a = 8, b = -24
Factorise:

17x - b = x(4a + 9) - 3a

Now try comparing coefficients of x.

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Updated: May 11, 2015
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