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    if I did incorrect working out for the final question but still arrived at the same answer, would I gain full marks?


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    (Original post by Simonium1010)
    Sorry I meant FP1 - its alright though I'm not as dumb as I seem
    Got FP1 aswell , how are you feeling for it?
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    (Original post by agg98)
    what was the graph transformation answer, was it 1/3 in the axis or 3 in the y axis
    both are applicable.


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    Unofficial mark scheme!? Everyone add bits in or correct me
    1) 4rt3 +4
    2i) graph, ii) -1/(x-2) iii) stretch sf 3 parallel to y axis or 1/3 parallel to x axis
    3i) 8 ii) -0.25 iii) 9/2
    4) x=27 x=-8
    5i) 5 ii) 6x-8y-29
    6) x=2 x=14/3 y=1 y=-13/3
    7a) -3x^2+10x-3 b) 1/48
    8i) graph ii) x<-1 x>1.5
    9i) a=13 ii) min iii) 1/3
    10i) (5,-2) radius 5 ii) show iii) 40
    Feel free to dispute, this is what I got though
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    what was the question for 1
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    (Original post by Simonium1010)
    Sorry I meant FP1 - its alright though I'm not as dumb as I seem
    ahhh haha it's cool, didn't think you were dumb for a second i was just so confused i thought maybe all my friends and i had it wrong xx
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    (Original post by Invest)
    both are applicable.

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    No, it's not 3 in y-axis. It's 1/3 in x for sure but if it was 3 in y-axis, it'd be 3 multiplied by (-1/x) which would end up being -3/x. However, you could have 1/3 stretch in the y-axis aswell as 1/3 multipled by (-1/x) will give you -1/3x.
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    for the question where k<-25, i put k>25, but noted b2-4ac< 0 etc, and came to near the right conclusion. how many marks would i drop out of 3 , just the 1?
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    (Original post by Alevelsssss)
    Unofficial mark scheme!? Everyone add bits in or correct me
    1) 4rt3 +4
    2i) graph, ii) -1/(x-2) iii) stretch sf 3 parallel to y axis or 1/3 parallel to x axis
    3i) 8 ii) -0.25 iii) 9/2
    4) x=27 x=-8
    5i) 5 ii) 6x-8y-29
    6) x=2 x=14/3 y=1 y=-13/3
    7a) -3x^2+10x-3 b) 1/48
    8i) graph ii) x<-1 x>1.5
    9i) a=13 ii) min iii) 1/3
    10i) (5,-2) radius 5 ii) show iii) 40
    Feel free to dispute, this is what I got though
    Im happy with that mate!
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    (Original post by Invest)
    if I did incorrect working out for the final question but still arrived at the same answer, would I gain full marks?


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    Unless the mark scheme specifically states for a method which it generally does not. Any non-specified method which reaches the correct answer will score full marks.
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    (Original post by Alevelsssss)
    Unofficial mark scheme!? Everyone add bits in or correct me
    1) 4rt3 +4
    2i) graph, ii) -1/(x-2) iii) stretch sf 3 parallel to y axis or 1/3 parallel to x axis
    3i) 8 ii) -0.25 iii) 9/2
    4) x=27 x=-8
    5i) 5 ii) 6x-8y-29
    6) x=2 x=14/3 y=1 y=-13/3
    7a) -3x^2+10x-3 b) 1/48
    8i) graph ii) x<-1 x>1.5
    9i) a=13 ii) min iii) 1/3
    10i) (5,-2) radius 5 ii) show iii) 40
    Feel free to dispute, this is what I got though
    For the transformation, it was sf 1/3 in either direction.
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    Im so paranoid that I put 1/48 instead of -1 now fml, better apply for mcdonalds
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    (Original post by Molly_xox)
    It wasn't just me! But yeah, everyone else I know got 40 so we're probably wrong. Did you get the distance from Q to P to be sq root 80 too?
    I did, using pythag, but seems like we're wrong! Although we must have got the right co-ordinates so can't have lost too many marks
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    (Original post by nurav11)
    No, it's not 3 in y-axis. It's 1/3 in x for sure but if it was 3 in y-axis, it'd be 3 multiplied by (-1/x) which would end up being -3/x. However, you could have 1/3 stretch in the y-axis aswell as 1/3 multipled by (-1/x) will give you -1/3x.
    Yes you are correct. my mistake. I had thought he said 1/3 in y-direction as that is also a correct answer.


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    Hey, I've added an unofficial mark scheme to the original post for easy access. The content is right but I really cannot remember the order of the questions (1-3, 6 and 10 are definitely correct though) so if anyone knows I've got the order wrong, please correct me and I will change it! Hope the exam went fine for everyone and don't forget there's a C2 thread here. Good luck for the rest of your exams
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    (Original post by Alevelsssss)
    Unofficial mark scheme!? Everyone add bits in or correct me
    1) 4rt3 +4
    2i) graph, ii) -1/(x-2) iii) stretch sf 3 parallel to y axis or 1/3 parallel to x axis
    3i) 8 ii) -0.25 iii) 9/2
    4) x=27 x=-8
    5i) 5 ii) 6x-8y-29
    6) x=2 x=14/3 y=1 y=-13/3
    7a) -3x^2+10x-3 b) 1/48
    8i) graph ii) x<-1 x>1.5
    9i) a=13 ii) min iii) 1/3
    10i) (5,-2) radius 5 ii) show iii) 40
    Feel free to dispute, this is what I got though
    So you're saying it was 1/48 as opposed to the others who said it's -1/48?

    Help!
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    7b) wasnt it -1/48 , because it was x^-1/3?
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    Can anyone remember how many marks the scale factor question was worth?. Also can someone explain briefly how on the K question the answer was -25/8
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    Do you remember what you got for 8) part iii. It was the one about working out K when their was no real roots
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    (Original post by AlfieH)
    So you're saying it was 1/48 as opposed to the others who said it's -1/48?

    Help!
    It was -1/48 since the differential was -1/3x^(-4/3). Inserting -8 as x gave you -1/3 * 1/(cube root -8)^4 = -1/3 * 1/16 = -1/48.
 
 
 
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