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    (Original post by jammymess)
    Hi, basically you just put x = 0 into the tangent and circle equations to get the co ordinates of the 3 points (because at the Y axis, x = 0)
    I've forgotten what they were specifically, but you end up with a triangle with base 10, and perpindicular height of 8.
    0.5 X B X H = 0.5 X 8 X 10 = 40 units^2
    Well that's what I put anyway, talking to other people after the exam some people got the same as me
    Thanks!
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    Anyone solve the simultaneous equations? I rearranged the 1st equation to equal y, subbed it in but couldn't solve the quadratic..

    I think I got like 3x^2 -20x +28 = 0
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    Would anyone know what mark and grade I would get overall? I didn't do the discriminant question and for the area question, I found out what P and R were and found out the lengths of the sides - but I didn't work out the area.

    For (5root5)^3 I got 5^9 as I had a logic that 5root5 = 125 then forgot to root it.
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    (Original post by Madhutty)
    Something like 6x + 8y - 29 = 0 ...?

    Might have switched the 6 and the 8 but 29 seems fairly memorable...
    That seems correct - I remember -10.5 then subtracting 4 making -14.5 then multiplying everything by 2 to make -29 so it's an integer.

    Seeing the responses it seems generally people found this exam reasonably difficult and from looking at past mark boundaries I suspect that the A Boundary will be around 60 or lower slightly lower.

    The last reasonably difficult papers were in 2011 and the boundaries then were A at 54 and 61 (January and June).

    Assuming that's right, 90 UMS will be somewhere around 65 - last year it was 69 and that was a much easier paper.
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    (Original post by Peppercrunch)
    Would anyone know what mark and grade I would get overall? I didn't do the discriminant question and for the area question, I found out what P and R were and found out the lengths of the sides - but I didn't work out the area.

    For (5root5)^3 I got 5^9 as I had a logic that 5root5 = 125 then forgot to root it.
    Could be an A still if you got everything else 100% correct.
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    20 root 5

    You have to find the distance PQ which is 4 root 5
    Then the distance between PR is 10
    Do 4 root 5 x 10 = 40 root 5
    Divided by 2 = 20 root 5
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    Yep that is right xx
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    Anyone else think last years paper was harder ? Or is it just me hahaa I resat this year got a C last year , the grade boundaries were so high last year ! Got 58/72 and got a C !!!
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    (Original post by Patsella)
    Anyone else think last years paper was harder ? Or is it just me hahaa
    I sat last years and this years and I felt like this years was harder.
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    For the inequality question i wrote
    X<-1 X>3/2

    And then underneath it i made a stupid mistake and wrote

    -1>x>3/2

    (Wrote it twice crossed it and wrote it a third time and kept it)

    Which answer will the examiner mark?
    Will i get any marks on this question?
    Is there a chance the examiner will ignore -1>x>3/2?


    Posted from TSR Mobile
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    (Original post by saqib1997)
    For the inequality question i wrote
    X<-1 X>3/2

    And then underneath it i made a stupid mistake and wrote

    -1>x>3/2

    (Wrote it twice crossed it and wrote it a third time and kept it)

    Which answer will the examiner mark?
    Will i get any marks on this question?
    Is there a chance the examiner will ignore -1>x>3/2?


    Posted from TSR Mobile
    If they're a nice examiner you might get full marks. Maybe lose 1.
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    (Original post by Yazmin123)
    I rearranged the linear equation for y and put it in the quadratic i got y=5-2x then expanded that and because there was a negative sign as it was x^2-y^2 i multiplied it all my -1 i dont know what i did wrong?
    And no i didn't get any of the correct values.
    y = 5 - 2x
    Sub in to x2 - y2 = 3

    x2 - (5 - 2x)2 =3 M1
    x2 - (25 - 20x + 4x2) = 3 A1
    x2 - 25 + 20x - 4x2 = 3
    -3x2 + 20x - 28 = 0 A1
    3x2 - 20x + 28 = 0
    3x2 - 6x - 14x + 28 = 0
    (3x - 14)(x - 2) = 0 M1
    x = 2 or 14/3 A1
    y = 1 or -13/3 A1

    This is likely to be the allocation of marks for this question.
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    (Original post by saqib1997)
    For the inequality question i wrote
    X<-1 X>3/2

    And then underneath it i made a stupid mistake and wrote

    -1>x>3/2

    (Wrote it twice crossed it and wrote it a third time and kept it)

    Which answer will the examiner mark?
    Will i get any marks on this question?
    Is there a chance the examiner will ignore -1>x>3/2?


    Posted from TSR Mobile
    The examiner will look at that as: 'This candidate knows two potential correct answers so they put both. The candidate does not know the correct answer.' You'll likely lose 2 marks.
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    (Original post by scrlk)
    Could be an A still if you got everything else 100% correct.
    I hope I pick up method marks for those I got wrong.
    Oh well, I can hope to do well in C2 and S1.
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    im more than confident it was -1/48
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    No it's 1/48 as it's -1/3 x -1/16 which is a plus
    (Original post by MacDaddy101)
    im more than confident it was -1/48
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    (Original post by rachelthorpe4)
    20 root 5

    You have to find the distance PQ which is 4 root 5
    Then the distance between PR is 10
    Do 4 root 5 x 10 = 40 root 5
    Divided by 2 = 20 root 5

    that is what i got but it is not a right angle triangle answer is 40
    • Thread Starter
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    (Original post by Patsella)
    No it's 1/48 as it's -1/3 x -1/16 which is a plus
    It was -1/48 since it was -1/3 * 1/16.
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    (Original post by MacDaddy101)
    im more than confident it was -1/48
    It is -1/48.
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    R is the tangent y intercept so
    3x+4y=32
    4y=-3x+32
    Y=-3/4x+8
    R co ordinate is (0,8)

    Q is the where the circle meets the y axis so x=0
    0^2+y^2-(10×0)+4y+4
    =y^2+4y+4
    =(y+2)(y+2)
    Y=-2

    So the distance between Q and R is 10
    And the distance between P and the y axis is 8

    Area = 0.5 × 10 × 8
    = 40 units squared


    At least thats what I think
 
 
 
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