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OCR (not MEI) C1 - Wednesday 13th May 2015

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Would anyone know what mark and grade I would get overall? I didn't do the discriminant question and for the area question, I found out what P and R were and found out the lengths of the sides - but I didn't work out the area.

For (5root5)^3 I got 5^9 as I had a logic that 5root5 = 125 then forgot to root it.
Reply 361
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Octan
2
Original post by Madhutty
Something like 6x + 8y - 29 = 0 ...?

Might have switched the 6 and the 8 but 29 seems fairly memorable...


That seems correct - I remember -10.5 then subtracting 4 making -14.5 then multiplying everything by 2 to make -29 so it's an integer.

Seeing the responses it seems generally people found this exam reasonably difficult and from looking at past mark boundaries I suspect that the A Boundary will be around 60 or lower slightly lower.

The last reasonably difficult papers were in 2011 and the boundaries then were A at 54 and 61 (January and June).

Assuming that's right, 90 UMS will be somewhere around 65 - last year it was 69 and that was a much easier paper.
Reply 362
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scrlk
7
Original post by Peppercrunch
Would anyone know what mark and grade I would get overall? I didn't do the discriminant question and for the area question, I found out what P and R were and found out the lengths of the sides - but I didn't work out the area.

For (5root5)^3 I got 5^9 as I had a logic that 5root5 = 125 then forgot to root it.


Could be an A still if you got everything else 100% correct.
20 root 5

You have to find the distance PQ which is 4 root 5
Then the distance between PR is 10
Do 4 root 5 x 10 = 40 root 5
Divided by 2 = 20 root 5
Yep that is right xx
Anyone else think last years paper was harder ? Or is it just me hahaa I resat this year got a C last year , the grade boundaries were so high last year ! Got 58/72 and got a C !!!
Reply 366
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Original post by Patsella
Anyone else think last years paper was harder ? Or is it just me hahaa


I sat last years and this years and I felt like this years was harder.
For the inequality question i wrote
X<-1 X>3/2

And then underneath it i made a stupid mistake and wrote

-1>x>3/2

(Wrote it twice crossed it and wrote it a third time and kept it)

Which answer will the examiner mark?
Will i get any marks on this question?
Is there a chance the examiner will ignore -1>x>3/2?


Posted from TSR Mobile
Reply 368
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Octan
2
Original post by saqib1997
For the inequality question i wrote
X<-1 X>3/2

And then underneath it i made a stupid mistake and wrote

-1>x>3/2

(Wrote it twice crossed it and wrote it a third time and kept it)

Which answer will the examiner mark?
Will i get any marks on this question?
Is there a chance the examiner will ignore -1>x>3/2?


Posted from TSR Mobile


If they're a nice examiner you might get full marks. Maybe lose 1.
Original post by Yazmin123
I rearranged the linear equation for y and put it in the quadratic i got y=5-2x then expanded that and because there was a negative sign as it was x^2-y^2 i multiplied it all my -1 i dont know what i did wrong?
And no i didn't get any of the correct values.


y = 5 - 2x
Sub in to x2 - y2 = 3

x2 - (5 - 2x)2 =3 M1
x2 - (25 - 20x + 4x2) = 3 A1
x2 - 25 + 20x - 4x2 = 3
-3x2 + 20x - 28 = 0 A1
3x2 - 20x + 28 = 0
3x2 - 6x - 14x + 28 = 0
(3x - 14)(x - 2) = 0 M1
x = 2 or 14/3 A1
y = 1 or -13/3 A1

This is likely to be the allocation of marks for this question.
Original post by saqib1997
For the inequality question i wrote
X<-1 X>3/2

And then underneath it i made a stupid mistake and wrote

-1>x>3/2

(Wrote it twice crossed it and wrote it a third time and kept it)

Which answer will the examiner mark?
Will i get any marks on this question?
Is there a chance the examiner will ignore -1>x>3/2?


Posted from TSR Mobile


The examiner will look at that as: 'This candidate knows two potential correct answers so they put both. The candidate does not know the correct answer.' You'll likely lose 2 marks.
Original post by scrlk
Could be an A still if you got everything else 100% correct.


I hope I pick up method marks for those I got wrong. :s-smilie:
Oh well, I can hope to do well in C2 and S1.
im more than confident it was -1/48
No it's 1/48 as it's -1/3 x -1/16 which is a plus
Original post by MacDaddy101
im more than confident it was -1/48
Original post by rachelthorpe4
20 root 5

You have to find the distance PQ which is 4 root 5
Then the distance between PR is 10
Do 4 root 5 x 10 = 40 root 5
Divided by 2 = 20 root 5



that is what i got but it is not a right angle triangle :frown: answer is 40
Reply 375
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c223
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Original post by Patsella
No it's 1/48 as it's -1/3 x -1/16 which is a plus


It was -1/48 since it was -1/3 * 1/16.
Original post by MacDaddy101
im more than confident it was -1/48


It is -1/48.
R is the tangent y intercept so
3x+4y=32
4y=-3x+32
Y=-3/4x+8
R co ordinate is (0,8)

Q is the where the circle meets the y axis so x=0
0^2+y^2-(10×0)+4y+4
=y^2+4y+4
=(y+2)(y+2)
Y=-2

So the distance between Q and R is 10
And the distance between P and the y axis is 8

Area = 0.5 × 10 × 8
= 40 units squared


At least thats what I think
Original post by Madhutty
y = 5 - 2x
Sub in to x2 - y2 = 3

x2 - (5 - 2x)2 =3 M1
x2 - (25 - 20x + 4x2) = 3 A1
[font=Franklin Gothic
Medium]x2 - 25 + 20x - 4x2 = 3

-3x2 + 20x - 28 = 0 A1
3x2 - 20x + 28 = 0
3x2 - 6x - 14x + 28 = 0

(3x - 14)(x - 2) = 0 M1
x = 2 or 14/3 A1
y = 1 or -13/3 A1

This is likely to be the allocation of marks for this question.

It was 5 marks wasn't it?
Reply 379
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scrlk
7
Original post by Peppercrunch
I hope I pick up method marks for those I got wrong. :s-smilie:
Oh well, I can hope to do well in C2 and S1.


Worst case scenario, you get a B in C1 (70 UMS).

You need 240 UMS for an A so you need to get 85 UMS in C2 and S1. :smile:

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