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    (Original post by rich1334)
    I put 6x-8y-29 I think
    Yeh that was it ) I put that too
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    (Original post by micycle)
    Were the simultaneous equations:

    2x+y=5 AND x^2-y^2=3

    OR

    2x+y=5 AND x^2+y^2=3
    first one!!!
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    (Original post by micycle)
    Were the simultaneous equations:

    2x+y=5 AND x^2-y^2=3

    OR

    2x+y=5 AND x^2+y^2=3
    The first one
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    (Original post by User10102929)
    Got -1/48 for this I think
    Grrr

    Anyone know how many marks this was out of?
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    Pretty sure it is this
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    (Original post by micycle)
    Were the simultaneous equations:

    2x+y=5 AND x^2-y^2=3

    OR

    2x+y=5 AND x^2+y^2=3
    2x+y=5 AND x^2-y^2=3
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    (Original post by Sayersss)
    Grade boundary expectations?

    Was an easy paper but subject to a fair few mistakes

    My estimate is around 65/66, same as last year
    I'd say the one last year was a lot easier. I'm hoping for 62/63.
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    (Original post by Brian luiz)
    I got both of those answers, im sure they are right.
    I got both of these too
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    can someone please do an unofficial mark scheme for this paper???/

    and how is A=13????
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    (Original post by AstroNandos)
    Grrr

    Anyone know how many marks this was out of?

    pretty sure it was 4
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    (Original post by Parallex)
    was that find the gradient of x^{1/3} when x=8?

    I got -1/48 for that

    Was it not -1/3?
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    So for part 2iii is stretch 1/3 parallel to y wrong??
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    (Original post by Parallex)
    pretty sure it was 4
    Oh. ****.
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    (Original post by lily9666768)
    first one!!!
    In which case, the simultaneous equation:


    = 2 & 14/3
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    A will be 66
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    (Original post by Dentist214)
    That gives me hope, would they need to be high A's in c2 and s1 like 65/72? Obviously depending on grade boundaries but never seen them higher than that
    65/72 was unusually high for a core 1 exam. They're normally 61/62 and s1 and core 2 A marks are normally 56-59
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    (Original post by AstroNandos)
    Was it not -1/3?

    yeah it was my bad!

    solution:

    f(x) = x^{-1/3}

f'(x) = (-1/3)x^{-4/3}

f'(8) = (-1/3)8^{-4/3}



8^{-4/3} = 1/16



(-1/3)(1/16) = -(1/48)
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    (Original post by AstroNandos)
    Was it not -1/3?
    Pretty surr i got-16/3 question was definitely x^-1/3

    Edit: I was wrong, eugh I've dropped so many stupid marks
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    (Original post by Katie.R.S.)
    So for part 2iii is stretch 1/3 parallel to y wrong??
    Yes its stretch of scale factor 1/3 parallel to x axis
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    (Original post by AstroNandos)
    Was it not -1/3?
    Dy/dx = -1/3x^-4/3

    Input 8:

    -1/3 x 1/16 = -1/48.

    Not sure if that's what I put in the exam but looking now it's quite straight forward..
 
 
 
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