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# Emergency help :'( watch

1. hi guys could some quickly help with this?!
2. (Original post by gandanmo2)
hi guys could some quickly help with this?!
Oooh, gosh, what a tiny picture

How far have you got? What have you tried so far?
3. (Original post by gandanmo2)
hi guys could some quickly help with this?!
You can do this in a number of ways but I would start by writing the numerator and denominator into the polar form equivalents ( e^itheta) and apply demoivres theorem to the top and bottom and simplify. Dividing two complex numbers so you take away the arguments and divide the moduli
4. I'm going to have a go at this question real quick, just say if you would like my solution, I might get it wrong though
z = (6i - 8)/25 and z=(10/25)e^(2.5i), does anyone else have any solutions to this? I am curious now
6. (Original post by AndyW123)
z = (6i - 8)/25 and z=(10/25)e^(2.5i), does anyone else have any solutions to this? I am curious now
Yes, that is correct...except the part in bold (not sure what you did there).
7. (Original post by a10)
Yes, that is correct...except the part in bold (not sure what you did there).
ahh i see! thanks exam in an hour eek

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