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    In an electrochemistry experiment the voltage between two electrodes is 10 Volts andthe current is 10 mA. Find the heat released after one minute.

    For this I have calculated resistance R=V/I = 10/0.01 = 1000 ohms

    and then used tV^2/R = 60*0.01^2 / 1000 = 0.000006

    is this correct?
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    (Original post by jacksonmeg)
    In an electrochemistry experiment the voltage between two electrodes is 10 Volts andthe current is 10 mA. Find the heat released after one minute.

    For this I have calculated resistance R=V/I = 10/0.01 = 1000 ohms

    and then used tV^2/R = 60*0.01^2 / 1000 = 0.000006

    is this correct?
    You need to post the full question if you want an answer.
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    (Original post by uberteknik)
    You need to post the full question if you want an answer.
    Umm.. this is the full question. In fact I copied and pasted it
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    (Original post by jacksonmeg)
    Umm.. this is the full question. In fact I copied and pasted it
    It's the word 'heat' which is ambiguous as it says nothing about the units the answer should be stated in. i.e. heat could be temperature difference or power or energy expended etc.

    I'm assuming it's energy released in this example:

    E = P \mathrm{\ x \ } t

    P = VI

    E = VIt

    E = 10 \mathrm{\ x \ } 10 \mathrm{x}10^{-3} \mathrm{\ x \ }60 = 6 \mathrm{\ Joules}

    Alternately:

    R = \frac{V}{I} = \frac{10}{0.01} = 1000 \Omega

    P = \frac{V^2}{R} = \frac{100}{1000} = 0.1 \mathrm{\ Watts}

    E = P \mathrm{\ x \ }t = 0.1 \mathrm{\ x \ }60 = 6 \mathrm{\ Joules}
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    (Original post by uberteknik)
    It's the word 'heat' which is ambiguous as it says nothing about the units the answer should be stated in. i.e. heat could be temperature difference or power or energy expended etc.

    I'm assuming it's energy released in this example:

    E = P \mathrm{\ x \ } t

    P = VI

    E = VIt

    E = 10 \mathrm{\ x \ } 10 \mathrm{x}10^{-3} \mathrm{\ x \ }60 = 6 \mathrm{\ Joules}

    Alternately:

    R = \frac{V}{I} = \frac{10}{0.01} = 1000 \Omega

    P = \frac{V^2}{R} = \frac{100}{1000} = 0.1 \mathrm{\ Watts}

    E = P \mathrm{\ x \ }t = 0.1 \mathrm{\ x \ }60 = 6 \mathrm{\ Joules}
    Ahh I see what you mean, thanks for the response !
 
 
 
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