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# Fun maths problem! watch

1. What is the smallest integer (non-zero) such that if you rotate the number to the left you get a number that is exactly one and a half times the original number?

(To rotate the number left, take the first digit off the front and append it to the end of the number. 3784 rotated to the left is 7843.)
2. Whas 9 plus 10?
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19.Nothing funny here.Move along...
3. (Original post by economist2)
Whas 9 plus 10?
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19.Nothing funny here.Move along...
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4. (Original post by lllllllllll)
What is the smallest integer (non-zero) such that if you rotate the number to the left you get a number that is exactly one and a half times the original number?

(To rotate the number left, take the first digit off the front and append it to the end of the number. 3784 rotated to the left is 7843.)
I get the same as the online solution - what's the condition they missed out?

Edit: I see you've changed your post.
5. (Original post by ghostwalker)
I get the same as the online solution - what's the condition they missed out?

Edit: I see you've changed your post.
Mwhahah, yes I did

Hint
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The original question wants an integer however it doesn't say that we have to use a decimal base 10 numbering system to find the smallest possible integer for which the conditions are true.

6. (Original post by lllllllllll)
Mwhahah, yes I did

Hint
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The original question wants an integer however it doesn't say that we have to use a decimal base 10 numbering system to find the smallest possible integer for which the conditions are true.

lol!
7. Wow, this is one large number

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1176470588235294
8. (Original post by lllllllllll)
Mwhahah, yes I did

Hint
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The original question wants an integer however it doesn't say that we have to use a decimal base 10 numbering system to find the smallest possible integer for which the conditions are true.

Spoiler:
Show

9. (Original post by ghostwalker)
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(Original post by Renzhi10122)
Wow, this is one large number
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1176470588235294
It's what I was thinking as well, ie if we work in binary to base-4 we can have an integer such that one-and-a-half of 12 = 21 which still answers the question correctly and it's the smallest since we can't go lower than 1s and 2s. Just wanted to see what other's thought of the idea

Yep, we get 1176470588235294 if we work in binary to base-10 which is really difficult to work with given that the number 10 has hardly any useful factors except from 2 and 1

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Updated: May 12, 2015
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