The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Edexcel C2 20th May 2015 *Official Thread*

Scroll to see replies

Original post by joeltyler14
Anyone else think that translations will come up as they didn't in C1, perhaps of the sine and cosine graphs.


Oh my, I thought exactly the same- Haha!! Yep, I think its v likely.

Posted from TSR Mobile
Original post by frozo123
This is what catches a lot of people out
the points where it crosses the x axis are -4,0,2
you can't just put the limits as 2 and -4
you have to solve for 0 and 2 and -4, 0

so 1. multiply out brackets
2. integrate
3. find area for each limit
4. add :smile:


Oh yeah!!! Oh gosh lol. :smile:

Posted from TSR Mobile
How do I do this? So far, I know that tanθ=1/(square root)3. How do I proceed from here?


Giving your answers in terms of π, solve the equation:

3 tan2 θ − 1 = 0,

for θ in the interval −π ≤ θ ≤ π. (6)
Original post by gdunne42
The formula page offers two expansions for a binomial. I assume you have learned to use both.
Use the (1 + x)^n version noting you have x/4 not just x and taking great care e.g. (x/4)^2 = x^2/16
Your answer will be in terms of n that you should simplify as much as possible.

For part b make the coefficient of x = the coefficient of the x^2 term and solve for n

Posted from TSR Mobile


Thank you sooooo much!!!


Posted from TSR Mobile
Original post by fire_and_ice
How do I do this? So far, I know that tanθ=1/(square root)3. How do I proceed from here?


Giving your answers in terms of π, solve the equation:

3 tan2 θ − 1 = 0,

for θ in the interval −π ≤ θ ≤ π. (6)


I thought it would be tan θ= 1/3 therefore = tan-1(1/3) so..

= 0.322 then find your solutions using the tan graph.

After you've found your solutions divide them all by 2. :smile:

I think that's right.. Well I hope anyway.

Posted from TSR Mobile
Original post by fire_and_ice
How do I do this? So far, I know that tanθ=1/(square root)3. How do I proceed from here?


Giving your answers in terms of π, solve the equation:

3 tan2 θ − 1 = 0,

for θ in the interval −π ≤ θ ≤ π. (6)


is that 3tan^2x - 1 or 3tan2x - 1? If it's 3tan2x -1 then:

I'll use 'x' instead of theta.

3tan2x - 1 = 0

3tan2x = 1

tan2x = 1/3

tan inverse (1/3) find the values and divide them by 2

or if it's squared then you can just do it the same way except square root your answers, right?
Original post by fire_and_ice
How do I do this? So far, I know that tanθ=1/(square root)3. How do I proceed from here?


Giving your answers in terms of π, solve the equation:

3 tan2 θ − 1 = 0,

for θ in the interval −π ≤ θ ≤ π. (6)


ImageUploadedByStudent Room1431786486.371597.jpg


Posted from TSR Mobile
Original post by ParisInc.


Oops forgot the minus sign on the last 5/6 pi


Posted from TSR Mobile
Original post by gdunne42
A. Use the formula for arc length.
B. Find the length of PQ. Hint make a triangle with the radius and use sine or cosine rule. Keep it in exact sure form. Add to the exact answer in part a.
C. Find the area of the sector and the area of the triangle and subtract. Work out the area of the circle and express one answer as a % of the other


Posted from TSR Mobile


Thanks bro
Original post by lulupixie
but when you put 0 into the equation you just get 0 leaving the -4 and 2??? Sorry these are probably stupid questions im not very confident with C2 :s-smilie:


yeah but you've subtracted them, you're meant to add them together
Original post by ParisInc.
ImageUploadedByStudent Room1431780599.446900.jpg

Please please please can somebody explain question 3 to me step by step because I really don't understand. I would be ETERNALLY GRATEFUL!!!!!


Posted from TSR Mobile


ImageUploadedByStudent Room1431786763.854482.jpg I hope this helps


Posted from TSR Mobile
Original post by ParisInc.
Oops forgot the minus sign on the last 5/6 pi


Posted from TSR Mobile


sorry probably a stupid question but why is it 5/6pi? I thought it was 180+theta for tan so it would be 7/6 pi?
Original post by ParisInc.


Thanks a lot, but I still don't understand how you worked out the last line?
Any predictions for the exam?
Original post by .JC.
Hi all, looking for a little help with factorials.

Doing a Solomon paper, and there is a binomial expansion of an equation where the power is 'n'.

I am stuck on working out what (nC2) is equal to. I have looked it up using wolfram alpha, and it equals 1/2(n-1)n which can also be written as n(n-1) all divided by 2. How do you get from the initial (nC2) to this solution? Thanks


Finding power of a binomial isnt in our spec for c2, its for c4. u dont need to know it
Original post by GCSE_2014
Any predictions for the exam?


1. Binomial expansion
2. Factor theorem
3. Trigonometric equations
4. Finding stationary points and maximum/minimum values
5. some question with a weird looking swimming pool that asks you to find the total area and/or perimeter using: length of an arc formula, area of a sector formula, cosine rule to find the length of a missing side.
6. trapezium rule
7. a question where they ask you to find the total area of a shaded region on a graph using integration
8. Logarithm question
9. equation of a circle question asks you to find the midpoint and radius
10. another weird shape involving circles and/or triangles that asks you find some angles or areas
11. Edit: forgot geometric sequences!

most of these things are likely to come up imo
(edited 8 years ago)
Has the paper been leaked or not is it true


Can someone show me where I can find more questions specifically like this one? :smile:
Untitled.png1.4KB
Original post by LearningGeek


Can someone show me where I can find more questions specifically like this one? :smile:


That was on my paper !


Posted from TSR Mobile
check on this document, unless you have already done them all lol

https://3f7c9b863b68ba81e37b9436bc95ae45e636d362.googledrive.com/host/0B1ZiqBksUHNYTUNwQTFfVl94WWc/Edexcel-Set-1/C2%20%20Sequences%20and%20series%20-%20Geometric%20series.pdf

Original post by LearningGeek


Can someone show me where I can find more questions specifically like this one? :smile:

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you