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AQA FP3 June 2015 Unofficial Mark Scheme

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Reply 60
anyone have the paper for this?
Reply 61
Original post by Lau14
There's some bits missing/not sure on and the wording isn't right but these are the questions as far as I know :smile:

Spoiler

Hey there, Do you have the exam paper or at least know what (?) is on question 6
Hi, I'm currently revision for this as I am sitting it in the summer.
Looking at this paper, can some one help me with question 2 please ?
I got my general solution to be -
y= (tan^4x + c ) / 4secx

But when I come to find c I get -1 + 8 root 2
Can some one explain where the 7 comes from please ?
Original post by Roxanne18
Hi, I'm currently revision for this as I am sitting it in the summer.
Looking at this paper, can some one help me with question 2 please ?
I got my general solution to be -
y= (tan^4x + c ) / 4secx

But when I come to find c I get -1 + 8 root 2
Can some one explain where the 7 comes from please ?


I think you've re-arranged the equation incorrectly, after integrating you should get y*sec x=(tan^4 x)/4 + c, then substitute in y = 2 and x = pi/3 and you should get 7/4 for your + c. It's always best to substitute in your initial conditions straight after you've integrated. That's true for both C4 and FP3.
Original post by TheLifelessRobot
I think you've re-arranged the equation incorrectly, after integrating you should get y*sec x=(tan^4 x)/4 + c, then substitute in y = 2 and x = pi/3 and you should get 7/4 for your + c. It's always best to substitute in your initial conditions straight after you've integrated. That's true for both C4 and FP3.


Okay thank you, I shall try that now (:

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