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    I'm having a lot of difficulties solving question 6(i) of this exam. The mark scheme is no help at all... I don't even know whether I'm going in the right direction or not. Can anyone please give me a hand?

    This is the exam:
    https://docs.google.com/viewerng/vie..._s14_qp_32.pdf
    This is the mark scheme:
    https://docs.google.com/viewerng/vie..._s14_ms_32.pdf

    And this is my working:


    Thanks in advance
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    (Original post by t.s.r.)
    I'm having a lot of difficulties solving question 6(i) of this exam. The mark scheme is no help at all... I don't even know whether I'm going in the right direction or not. Can anyone please give me a hand?

    This is the exam:
    https://docs.google.com/viewerng/vie..._s14_qp_32.pdf
    This is the mark scheme:
    https://docs.google.com/viewerng/vie..._s14_ms_32.pdf

    And this is my working:


    Thanks in advance
    A is the centre for the arc BC so AB=AC=r Does that help ?
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    (Original post by brianeverit)
    A is the centre for the arc BC so AB=AC=r Does that help ?
    Let AB=AC=R then R=2r\cos x\text{and }2R+2xR=\pi  R
    Can you finish it from here ?
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    (Original post by brianeverit)
    Let AB=AC=R then R=2r\cos x\text{and }2R+2xR=\pi  R
    Can you finish it from here ?
    But why is R=2rcos x? Which formula are you using :confused:
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    (Original post by t.s.r.)
    But why is R=2rcos x? Which formula are you using :confused:
    AB is a chord of a circle. How do you find the length of a chord ?
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    (Original post by Ali97)
    Questions?
    No, got it. Thank you very much =)


    (Original post by brianeverit)
    AB is a chord of a circle. How do you find the length of a chord ?
    Oh, okay! Thanks, I got it xD
 
 
 
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