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    Very simple hypothesis testing question but due to the lack of examples and answers we've been given I can't work out how to it so kind of need a step by step guide if someones happy to help

    The mean height of 20 male students was found to be 1.71m with a standard deviation of 2cm. Does this evidence support (at the 5% significance level) the belief that the mean height of all men is 1.7m? (This is a two-tail test.)
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    (Original post by DJC)
    Very simple hypothesis testing question but due to the lack of examples and answers we've been given I can't work out how to it so kind of need a step by step guide if someones happy to help

    The mean height of 20 male students was found to be 1.71m with a standard deviation of 2cm. Does this evidence support (at the 5% significance level) the belief that the mean height of all men is 1.7m? (This is a two-tail test.)
    What would be the proposed distribution of the mean for the 20 students?
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    I think the mean height is normally distributed. (Because we've been told the s.d, something we wouldn't get if we had to do a t-test!)

    H0: u = 1.71
    H1: u is not 1.71

    So we want to test: \displaystyle z=\frac{\overline{X}-u}{\sigma /\sqrt{n}}.

    Can you use the information you have been given to work out what z is?
    Do you know how to get the required value from the normal tables?
 
 
 
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