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    How do I work this question out:
    Boric acid (H3BO3) can react with sodium hydroxide to form sodium borate and water. Write an equation for this reaction.
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    4 H3BO3 + 2 NaOH ---> Na2B4O7 + 7 H2O

    An acid and a base react in a neutralisation reaction to form a salt and water.

    Hope this helps


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    (Original post by lydiafoof)
    How do I work this question out:
    Boric acid (H3BO3) can react with sodium hydroxide to form sodium borate and water. Write an equation for this reaction.
    H3BO3 + 3NaOH .....
 
 
 
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