# Maths Mechanics A Level

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#1
Particles A and B are attached to a light inextensible string. The sting passes over a smooth fixed pulleys. The particles are released from rest, with the string taut, and A and B are at the same height above the horizontal floor. In subsequent motion, A descend with acceleration 1.4ms^-2 and strikes the floor 0.8s after being released. B never reaches the pulley.

The pulley has mass 0.5kg, and is held in a fixed position by a light vertical chain. Calculate the tension in the chain...immediately after A strikes the floor.
(Tension in the string before is 5.88N and i worked out the masses of A and B)

However in the mark scheme they don't include the masses of A and B working this out, but include the tension in the string:
T-4.9-(2x5.88)= 0
T=16.66N

Why is this?
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5 years ago
#2
You're more likely to get responses if you post in the maths forum
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