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    I'm stuck on 8(I) 😳.
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    Posted from TSR Mobile
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    Did you try to use the Area of a sector formula? Area=1/2r^2x
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    (Original post by alishahussain832)
    Did you try to use the Area of a sector formula? Area=1/2r^2x


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    Oh yeah Ty.
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    (Original post by alishahussain832)
    Did you try to use the Area of a sector formula? Area=1/2r^2x


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    Wait a minute, is the angle sin,cos, or tan?How would I know?
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    use area = \frac{1}{2}abSinC
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    Bro, is the answer 2.4470943..

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    Bro, you know two sides of the triangle and the angle in between

    Use 0.5 ab sinc = 8

    Solve for c

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    Sin(c) = 16/25

    Be careful here. Arcsin 16/25 will give you the principle value i.e. an acute angle... But you want the obtuse one so find it using the quadrant method

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    Whats the answer brother kadak :hmmm:

    Why you blanking me:sigh:

    What did i ever do to you to deserve this :dontknow:
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    (Original post by husband material)
    Whats the answer brother kadak :hmmm:

    Why you blanking me:sigh:

    What did i ever do to you to deserve this :dontknow:
    Posted from TSR Mobile


    Posted from TSR Mobile

    Oh sorry. I was revising.The answer was 2.45, when rounded to 3rd.Ty very much!
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    (Original post by Kadak)
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    Oh sorry. I was revising.The answer was 2.45, when rounded to 3rd.Ty very much!
    No worries

    But do you understand how to get the answer :hmmm:

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    (Original post by husband material)
    No worries

    But do you understand how to get the answer :hmmm:

    Posted from TSR Mobile


    Posted from TSR Mobile

    Yes 😃.I do now :yes:.
 
 
 
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