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    Stuck on part iv.Which x values Do I use? I have three!
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    Part ic of what?

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    (Original post by somegirlcalledea)
    Part ic of what?

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    Sorry I mean( iv).
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    You should have divided by (x-3), got a quadratic and linear factor, worked out the quadratic factor, which would of got you the points of intersection at when y=0. Then You have to work out it out using calculus. Split them in two equations
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    (Original post by Kadak)
    Stuck on part iv.Which x values Do I use? I have three!
    Find the area between the 1st x value and the 2nd value, and then the area between the 2nd and 3rd x value
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    If you integrate from the lowest to the highest x coordinate some of the area will cancel out, as the area in the negative y region is treated as negative so that when you sum with the integral it will be taken away. You have to separately integrate from the lowest to the middle, then the middle to the highest
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    integral between your -1 and 1/4 then add to the integral between 1/4 and 3
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    Should get something like this:

 
 
 
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